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3 years ago

Calculate the acceleration due to gravity on venus. the radius of venus is about 6.06 x 106 m and its mass is 4.88 x 1024 kg.

1 answer:

Elena-2011 [213]3 years ago

7 0

The formula for the acceleration due to gravity is:

a = Gm/r²
where
G is the universal gravitational constant = 6.6726 x 10⁻¹¹ N-m²/kg²
m is the mass of venus
r is the radius of venus

Substituting the values,

a = (6.6726 x 10⁻¹¹ N-m²/kg²)(4.88x10²⁴ kg)/(6.06x10⁶ m)²
<em>a = 8.87 m/s²</em>

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Some car manufacturers claim that their vehicles could climb a slope of 42 ∘. For this to be possible, what must be the minimum

Paladinen [302]

Answer:

D. 0.9

Explanation:

Calculating minimum coefficient of static friction, we first resolve the forces (normal and frictional) acting on the vehicle at an angle to the horizontal into their x and y components. After this, we can now substitute the values of x and y components into equation of static friction. Diagrammatic illustration is attached.

Resolving into x component:

∑ $F_{x} = F_{s} - mgsin\alpha =0$

$F_{s} = mgsin\alpha$ ------(1)

Resolving into y component:

∑ $F_{y} = F_{n} - mgcos\alpha =0$

$F_{n} = mgcos\alpha$ ------(2)

Static frictional force, $F_{s} \leq$ μ $F_{n}$ ------(3)

substituting $F_{s}$ from equation (1) and $F_{n}$ from equation (2) into equation (3)

$mgsin\alpha \leq$ μ $mgcos\alpha$

$sin\alpha \leq$ μ $cos\alpha$

μ $\geq \frac {sin\alpha}{cos\alpha}$

μ $\geq tan\alpha$

The angle the vehicles make with the horizontal α = 42°

μ ≥ tan 42°

μ ≥ 0.9

6 0

3 years ago

Describe how Newton’s third law applies to the box and the table.

Snowcat [4.5K]

Answer:

the box has vertical force on the table

Explanation:

There can be no single isolated force, for every action there must be a force of reaction of ingual magnitude and direction, but in the opposite direction

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3 years ago

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valentinak56 [21]

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4 years ago

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