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Strike441 [17]
3 years ago
13

Suppose you stir a little baking soda into water until the water looks clear again. How could you prove to someone that the clea

r material is a solution, not a compound?
Chemistry
2 answers:
HACTEHA [7]3 years ago
4 0
You can prove this by letting the water evaporate or using a instrument that can measure the solids in a liquid.
7nadin3 [17]3 years ago
3 0

Explanation:

A solution is defined as the substance formed due to addition of two or more number of substances. A solution is a homogeneous mixture.

And, homogeneous mixtures are always clear solution. Particles of a homogeneous solution never combine chemically with each other.

For example, when we dissolve baking soda in water then it will completely dissolve in water forming a clear solution.

So, in order to determine that it is a solution we can let the water from the solution to evaporate.

This will leave behind the solute, that is, baking soda in the vessel. This will show that it is a solution.

Whereas a compound is defined as the substance in which different elements are chemically combined together in a fixed ratio by mass.

For example, MgSO_{4} is a compound and elements are present in 1:4 ratio.

Components of a compound can only be separated by chemical means and not by any physical means.

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Calculate the ph of a buffer that is 0.145 m hc2h3o2 and 0.202 m kc2h3o2. The ka for hc2h3o2 is 1.8 × 10-5.
koban [17]

Answer:

pH = 4.8

Explanation:

A buffer is formed by a weak acid (0.145 M HC₂H₃O₂) and its conjugate base (0.202 M C₂H₃O₂⁻ coming from 0.202 M KC₂H₃O₂). The pH of a buffer system can be calculated using Henderson-Hasselbalch's equation.

pH = pKa + log\frac{[base]}{[acid]} \\pH = -log(1.8 \times 10^{-5} )+log(\frac{0.202M}{0.145M} )\\pH=4.8

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2 years ago
The density of mercury is 13.5 g/mL and the density of water is 1.00 g/mL. If a mercury barometer reads 677 mmHg, what is the ba
natulia [17]
<span>802 mm Hg X 13.5/1 = 10827 mm H2O X (1 cm/10 mm) = 1083 cm H2O = 1.08 X 10^3 cm H2O</span>
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Vladimir79 [104]

Answer:

B. It is highly flammable.

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Chemical properties deal with how the substance will behave when brought into contact with other substances, and usually have to do with it undergoing some kind of reaction. Flammability is a chemical property.

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