Question

What is mb for CH3NH2….

Answer 1

Answer:

A.) $K_b = \frac{[CH_3NH_3^+][OH^-]}{[CH_3NH_2]}$

Explanation:

The general Kb expression is:

$K_b = \frac{[HA][OH^-]}{[A^-]}$

In this equation

-----> Kb = equilibrium constant

-----> [HA] = acid

-----> [A⁻] = base

Since liquids are not included in equilibrium expressions, H₂O should not be present. The products are in the numerator while the reactant are in the denominator. In this reaction, CH₃NH₂ is acting as a base and CH₃NH₃⁺ is acting as an acid.

As such, the expression is:

$K_b = \frac{[CH_3NH_3^+][OH^-]}{[CH_3NH_2]}$