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wolverine [178]
2 years ago
9

What is the maximum radiation pressure exerted by sunlight in space ( s = 1350 w/m 2) on a flat black surface? a. 2. 25 × 10−5 p

a b. 4. 5 × 10−6 pa c. 9. 0 × 10−6 pa d. 0. 06 pa e. 7 × 10−4 pa
Chemistry
1 answer:
mel-nik [20]2 years ago
8 0

The maximum radiation pressure exerted by sunlight in space on a flat black surface is  4.5 × 10^{-6}  P a. So, the correct option is (b).

Radiation pressure is the name for the force electromagnetic wave particles exert on a surface. It is inversely related to the wave's speed. Given data

Solar constant  ( S )  =  1350W / m ^2

Now, the radiaton pressure is given by

P = 2 S /c

where c is the speed of the light

P = 2 × 1350 /3 × 10 ^8

P = 9 × 10^{-6}  P a

For a black surface, P = 4.5× 10^{-6}  P a

Therefore, maximum radiation pressure exerted by sunlight in space on a flat black surface is  4.5 × 10^{-6}  P a

Learn more about radiation pressure here;

brainly.com/question/23972862

#SPJ4

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15 pts The drop down items have the same options for all sections labeled choose an item
cricket20 [7]

8) 21.504 liters of gas

9) 122.5 g

10) 6.022*10^23

Explanation:

8)

1 mole= 22.4 liters

to calculate the volume of gas of 0.960 moles of CH4

22.4*0.960/1

= 21.504 liters of gas  

9)

2.0 mole*18.02 g/ 1 mole

=122.5 g

10)

2.0 l * 1 mole/22.4 l

6.022*10^23

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3 years ago
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hichkok12 [17]
What question? Lhh this is hilarious.
4 0
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Mario places 10 mL of water in a test tube and heats the liquid over a Bunsen burner for 2 minutes. After removing the test tube
monitta
Mario places 10 mL of water in a test tube and heats the liquid over a Bunsen burner for 2 minutes. After removing the test tube from the Bunsen burner, there are 6 mL of water left in the test tube. This experiment is a good example of a <span>physical change involving phase changes. </span>
6 0
3 years ago
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At what temp will a gas be at if you allow it to expand from an original 456 mL to 65°C to 3.4 L
alexira [117]
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Substituting the known values,
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The temperature is -14°C the air pressure in an automobile tire is 149K PA if the volume does not change what is the pressure af
Jet001 [13]

Answer: The pressure after the tire is heated to 17.3°C is 167 kPa

Explanation:

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=149kPa\\T_1=-14^0C=(273-14)=259K\\P_2=?=27.5psi\\T_2=17.3^0C=(273+17.3)=290.3K

Putting values in above equation, we get:

\frac{149}{259}=\frac{P_2}{290.3}\\\\P_2=167kPa

Hence, the pressure after the tire is heated to 17.3°C is 167 kPa

4 0
3 years ago
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