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wolverine [178]
1 year ago
9

What is the maximum radiation pressure exerted by sunlight in space ( s = 1350 w/m 2) on a flat black surface? a. 2. 25 × 10−5 p

a b. 4. 5 × 10−6 pa c. 9. 0 × 10−6 pa d. 0. 06 pa e. 7 × 10−4 pa
Chemistry
1 answer:
mel-nik [20]1 year ago
8 0

The maximum radiation pressure exerted by sunlight in space on a flat black surface is  4.5 × 10^{-6}  P a. So, the correct option is (b).

Radiation pressure is the name for the force electromagnetic wave particles exert on a surface. It is inversely related to the wave's speed. Given data

Solar constant  ( S )  =  1350W / m ^2

Now, the radiaton pressure is given by

P = 2 S /c

where c is the speed of the light

P = 2 × 1350 /3 × 10 ^8

P = 9 × 10^{-6}  P a

For a black surface, P = 4.5× 10^{-6}  P a

Therefore, maximum radiation pressure exerted by sunlight in space on a flat black surface is  4.5 × 10^{-6}  P a

Learn more about radiation pressure here;

brainly.com/question/23972862

#SPJ4

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In Experiment 9, a 1.05 g sample of a mixture of NaCl (MW 58.45) and NaNO2 (MW 69.01) is reacted with excess sulfamic acid. The
Kaylis [27]

Answer:

There is 76.6 mL of nitrogen collected

Explanation:

<u>Step 1: </u>Data given

Mass of the sample = 1. 05 grams

The sample is 40.00% by mass NaNO2

MW of NaCl = 58.45 g/mol

MW of NaNO2 = 69.01 g/mol

Temperature = 22.0 °C

Pressure = 750.0 mmHg = (750/760) atm

The vapor pressure of water at 22.0°C is 19.8 mm Hg = 0.02605 atm

<u>Step 2:</u> Calculate mass of NaNO2

(40/100)*1.05  = 0.42 grams

<u>Step 3:</u> Calculate moles of NaNO2

Moles NaNO2 = 0.42 grams / 69.01 g/mol

Moles NaNO2 = 0.00608 moles

<u>Step 4:</u> Calculate moles of N2

For 2 moles of NaNO2 we'll get 1 mol of N2

For 0.00608 moles of NaNO2 we'll get 0.00608/2 = 0.00304 moles

<u>Step 5:</u> Calculate pressure of N2

P = 750.0 - 19.8 = 730.2 mmHg = (730.2/760)atm = 0.96079 atm = 97352 Pa

<u>Step 6:</u> Calculate volume of N2

PV = nRT

⇒ P = the pressure of N2 =  0.96079

⇒ V = the volume of N2 = TO BE DETERMINED

⇒ n = moles of N2 = 0.00304 moles

⇒ R = the gas constant = 0.08206 L*atm/K*mol

⇒ T = the temperature = 22°C = 295 Kelvin

V = (0.00304*0.08206*295)/0.96079

V = 0.0766 L = 76.6 mL

There is 76.6 mL of nitrogen collected

4 0
3 years ago
What will be the end product for each electrode after electrolysis if the solution is concentrated aqueous sodium chloride ?​
Eddi Din [679]

Answer:

Cathode: Hydrogen gas

Anode: Chlorine gas

Explanation:

① Write down the ions present in the electrolyte

Cations: Na⁺, H⁺

Anions: Cl⁻ , OH⁻

② Decide which ions are preferentially discharged.

These are the factors:

For the discharge of cations,

- Reactivity series

(The lower the position of the cation in the reactivity series, the easier it is to be discharged)

For the discharge of anions,

- Concentration effect (look at this first)

(The more concentrated the ion, the easier for it to be discharged)

- If solution is not concentrated (dilute), look at the position of the anion on the electrochemical series.

(The lower the position of the anion on the electrochemical series, the easier of it to be discharged)

In this case:

For cations, H⁺ ions are selectively discharged at the cathode as its position is lower than Na⁺ in the reactivity series.

Anion: Cl⁻ ions, being more concentrated, are selectively discharged at the anode.

☆For electrolysis,

Cation at the cathode (-ve terminal)

Anion at the anode (+ve terminal)

In summary, here's what happened at each electrode:

<u>C</u><u>athode</u>

- H⁺ selectively discharged

- ionic half equation: 2H⁺ (aq) +2e⁻ → H₂ (g)

<u>Anode</u>

- Cl⁻ ions selectively discharged

- ionic half equation: 2Cl⁻ (aq) → Cl₂ (g) + 2e⁻

3 0
3 years ago
There are many compounds that contribute to the overall aroma of a banana. The primary compound is called isoamyl acetate and co
Murljashka [212]

Explanation:

Let the mass of isoamyl acetate be 100g.

Moles of Carbon = 60.58/12 = 5.048mol

Moles of Hydrogen = 7.07/1 = 7.07mol

Moles of Oxygen = 32.28/16 = 2.018mol

Mole Ratio of C : H : O

= 5.048 : 7.07 : 2.018

= 5 : 7 : 2.

Hence the empirical formula of isoamyl acetate is C5H7O2.

8 0
2 years ago
Is there any way the pandemic helps this society?<br><img src="https://tex.z-dn.net/?f=22%20%5Ctimes%2012" id="TexFormula1" titl
Alexxandr [17]

Answer:

u meant the answer to this ques

Explanation:

22

×12

------

44

22 ×

----------

264

-----------

or the answer can be 22×12=264

7 0
3 years ago
PLEASE HELP!!!
Nataly [62]
1. research question
2. background research
3. hypothesis
4. <span>Controlled experiment 
5. data analysis 
6. data collection
7. conclusion</span>
7 0
3 years ago
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