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artcher [175]
3 years ago
11

Which statement represents how light travels? Light given off from a moving source will travel faster in a vacuum. Light given o

ff from a moving source will travel faster in air. Light travels slower if the light source is moving. Light travels at the same speed even if the light source is moving.
Physics
2 answers:
BartSMP [9]3 years ago
7 0

Answer:

Light travels at the same speed even if the light source is moving.

Explanation:

I took the test, hope this helps :)

Debora [2.8K]3 years ago
4 0

Answer:

the first one

Explanation:

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The smallest division value of electronic balance​
lara [203]

Answer:

0.1g to 0.0000001g hope it helps uu

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The particles that make up protons and neutrons and are thought to be basic units of matter are
Dmitry_Shevchenko [17]
The correct answer that would best complete the given statement above is the term QUARKS. The particles that make up protons and neutrons and are thought to be basic units of matter are quarks. <span>A quark is an elementary particle and a fundamental constituent of matter. Hope this answers your question. Have a great day!</span>
3 0
3 years ago
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An object with a mass of 5.0 kg accelerates 8.0 m/s² when an uknown force is applied to it. what is the amount of the force?​
Harman [31]
  • Mass=5kg
  • Acceleration=8m/s^2

Using newtons second law

\\ \sf\longmapsto Force=Mass\times Acceleration

\\ \sf\longmapsto Force=5(8)

\\ \sf\longmapsto Force=40N

5 0
3 years ago
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Compare the momentums of a 50 kg dolphin swimming at 16.4 m/s and a 4100 kg elephant walking 0.20 m/s?
Mamont248 [21]
Their momentum is the same. 
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momentum of elephant=4100kg*0.20m/s=820kg*m/s
6 0
3 years ago
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13.An airplane starts from rest at the end of a runway and accelerates at a constant rate. In the first second, the airplane tra
Murrr4er [49]

Answer:

The answer is 3.33m

Explanation:

The acceleration "a" is constant.

Acceleration is the variation of velocity over time,

\frac{dv}{dt} = a.

solving the last equation

\int_{v_0}^v dv = a\int_0^t dt \rightarrow v-v_0 = at,

where v_0=0 because the airplane starts from rest.

Once again, velocity is the variation of distance over time.

\frac{dx}{dt} = at \rightarrow \int_{x_0}^x dx = a\int_0^t t\ dt

then

x- x_0 = \frac{1}{2}at^2

where x_0=0 if we consider  the end of the runway as the initial point (this step is for simplicity but you can let it expressed, it's going to cancel anyway).

If x=1.11\ m at t=1s, then

a = \frac{2x}{t^2} = 2.22\ m/s^2

and the final expression for the distance is

x = 1.11 t^2.

If t = 2s, x = 4.44 m. Which means thad the additional distance is

x(2s) - x(1s) = 4.44 - 1.11 = 3.33\ m

8 0
4 years ago
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