Answer:
1373.4 N/m
Explanation:
Hooke's law states that the extension of a spring and force are related by the expression, F=kx where k is spring constant, x is extension of spring and F is the applied force. Making k the subject of the formula then
Also, F=gm hence the above formula is modified as
Taking g as 9.81 m/s2 , x as 0.5 m and m as 70 kg then
If you look on the periodic table you will see the top group elements depending on how the elements relate to each in the column. All of the elements in that column show they all have 1 electron in their valence shell. Some of the chemicals in that family or group are Sodium, Lithium, Potassium. The are very reactive because they only have one electron and what 7 more to become stable.
<h2>Answer: The separation of the components of the nucleous of the atom </h2><h2>
</h2>
The n<u>uclear fission</u> consists of dividing a heavy nucleus into two or more lighter or smaller nuclei, by means of the <u>bombardment with neutrons to make it unstable.
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Then, with this division a great release of energy occurs and the emission of two or three neutrons, other particles and gamma rays.
It should be noted that in the process, the emitted neutrons can interact with new fissionable nuclei that will emit new neutrons and so on. Effect better known as chain reaction.
Answer:
Climate is determined by averaging the seasonal weather conditions for a region over a period of many ______ years
Choose the correct association for: dense bushes rain forest or jungle
Choose the correct association for: plains savanna
Answer:
The final temperature of both objects is 400 K
Explanation:
The quantity of heat transferred per unit mass is given by;
Q = cΔT
where;
c is the specific heat capacity
ΔT is the change in temperature
The heat transferred by the object A per unit mass is given by;
Q(A) = caΔT
where;
ca is the specific heat capacity of object A
The heat transferred by the object B per unit mass is given by;
Q(B) = cbΔT
where;
cb is the specific heat capacity of object B
The heat lost by object B is equal to heat gained by object A
Q(A) = -Q(B)
But heat capacity of object B is twice that of object A
The final temperature of the two objects is given by
But heat capacity of object B is twice that of object A
Therefore, the final temperature of both objects is 400 K.
