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xxMikexx [17]
1 year ago
11

The alkali metals play virtually the same general chemical role in all their reactions. (b) How is it based on atomic properties

?
Chemistry
1 answer:
vfiekz [6]1 year ago
6 0

b) It is based on atomic properties as alkali metals requires 7 more electrons to complete their outer orbit. And they try to give those electrons to other elements to obtain noble gas configuration.

Noble gases are the gases which do not react easily with anything. They are also called as Inert gases, and belongs to group 18 of the periodic table.

Alkali metals are the substances which are found in Group I of a periodic table. Mostly the elements which are present are:

  • Lithium (Li)
  • Sodium (Na)
  • Potassium (K)
  • Rubidium (Rb)
  • Cesium (Cs)
  • Francium (Fr)

Properties of alkali metals are:  Soft, shiny reactive metals. They are soft enough to cut with knife. Metals react with water and air quickly and gets tarnish, so pure metals are stored in container by dipping them in oil to prevent oxidation.

To know more about Alkali metals, refer to this link:

brainly.com/question/18153051

#SPJ4

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The table shows a chemical equation and the dimensional analysis used by a student to calculate the number of moles of Ba3N2 req
UNO [17]

This problem is providing the chemical reaction whereby barium nitride reacts with water to produce barium hydroxide and ammonia, so the number of moles of barium nitride are required in order to produce 8.3 moles of ammonia. It asks for us to evaluate the student's setup, so we conclude the answer is C. "1 mol of NH3 should be replaced with 2 mol of NH3", according to:

<h3>Mole ratios:</h3>

In chemistry, stoichiometric calculations are used to figure out the moles or mass of a substance, given information about another one in the reaction. In this case, for the given chemical equation:

Ba_3N_2 + 6H_2O \rightarrow 3Ba(OH)_2 + 2NH_3

We evidence a 1:2 mole ratio of barium nitride to ammonia, for that reason, the student's setup:

8.3 mol NH_3 * \frac{1 mol Ba_3N_2 }{1 mol NH_3}

Is incorrect, because the ammonia must be accompanied by a 2 rather than the 1 it is given there:

8.3 mol NH_3 * \frac{1 mol Ba_3N_2 }{2mol NH_3}

Thereby, the correct answer is C. "1 mol of NH3 should be replaced with 2 mol of NH3"

Learn more about mole ratios: brainly.com/question/15288923

5 0
2 years ago
How much heat is lost when 575 grams molten iron at 1825 k becomes solid iron at 293 k? The melting point or iron is 1811 k.​
Galina-37 [17]

Answer:

146 kJ  

Explanation:

There are two heat flows in this question.  

Heat lost on cooling + heat lost on solidifying = 0  

                 q₁              +                 q₂                   = 0  

              mCΔT          +             nΔHsol              = 0  

Data:  

       m = 575 g  

       C = 0.449 J·K⁻¹g⁻¹  

    T_i = 1825 K  

    T_f = 1811 K  

ΔHsol = -13.8 kJ·mol⁻¹  

Calculations:  

(a) Heat lost on cooling  

ΔT = T_f - T_i = 1811 K - 1825 K = -14 K  

q₁ = mCΔT = 575 g × 0.449 J·K⁻¹g⁻¹ × (-14 K) = -361 J = -3.61 kJ  

(b) Heat lost on solidifying  

n = \text{575 g} \times \dfrac{\text{1 mol}}{\text{55.84 g}} = \text{10.30 mol}\\\\q_{2} = n\Delta_{\text{sol}}H = \text{10.30 mol} \times \dfrac{\text{-13.8 kJ}}{\text{1 mol}}= \text{-142.1 kJ}

(c) Total heat lost  

q = q₁ + q₂ = -3.61 kJ - 142.1 kJ = -146 kJ  

The heat lost was 146 kJ.

 

5 0
2 years ago
Liquid A is known to have a lower surface tension and lower viscosity than Liquid B. Use these facts to predict the result of be
Korvikt [17]

Answer: Option (B) is the correct answer.

Explanation:

Surface tension is defined as the attractive forces experienced by the surface molecules of a liquid by the molecules present beneath the surface layer of the liquid.

And, viscosity is defined as the ability of a liquid to resist its flow. When a substance has high viscosity then it is known as a viscous substance.

Since, it is given that viscosity of liquid B is more than liquid A. Therefore, liquid B has more resistive force on its surface as compared to liquid A. As a result, time taken by liquid B is more than time taken by liquid A.

Also,    Surface tension = \frac{Force}{Length}

Surface tension of liquid B is more than liquid A. Therefore, F_{B} > F_{A}.

Thus, we can conclude that tA will be less than tB.

8 0
3 years ago
The volume of an automobile air bag was 66.8 L when inflated at 25 °C with 77.8 g of nitrogen gas. What was the pressure in the
Ray Of Light [21]

Answer:

\large \boxed{\text{103 kPa}}

Explanation:

We can use the Ideal Gas Law — pV = nRT

Data:

V = 66.8 L

m = 77.8 g

T = 25 °C

Calculations:

(a) Moles of N₂

\text{Moles of N}_{2} = \text{77.8 g N}_{2} \times \dfrac{\text{1 mol N}_{2}}{\text{28.01 g N}_{2}} = \text{2.778 mol N}_{2}

(b) Convert the temperature to kelvins

T = (25 + 273.15) K = 298.15 K

(c) Calculate the pressure

\begin{array}{rcl}pV & =& nRT\\p \times \text{66.8 L} & = & \text{2.778 mol} \times \text{8.314 kPa$\cdot$ L$\cdot$K$^{-1}$mol$^{-1}\times$ 298.15 K}\\66.8p & = & \text{6886 kPa}\\p & = & \textbf{103 kPa}\end{array}\\\text{The pressure in the bag is $\large \boxed{\textbf{103 kPa}}$}

3 0
2 years ago
Which of the following ratios are needed to determine the mass of oxygen produced from the decomposition of 10 grams of potassiu
Zielflug [23.3K]

The ratios which are needed to determine the mass of oxygen produced from the decomposition of 10 grams of potassium chlorate are;

  • 31.998 g O2 : 1 mole O2
  • 3 mole O2 : 2 mole KClO3
  • 112.55 g KClO31 mole KClO3

From stoichiometry;

  • We can conclude that according to the reaction;

3 moles of oxygen requires 2 moles of KClO3 to be produced.

And from molar mass analysis;

  • 31.998 g O2 is equivalent to 1 mole O2
  • O2112.55 g KClO3 is equivalent to 1 mole KClO3

Read more:

brainly.com/question/9920155

7 0
2 years ago
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