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emmainna [20.7K]
1 year ago
7

In an LRC circuit, why does the sum of the voltages around the circuit not equal the applied voltage as kirchhoff’s rule require

s?
Physics
2 answers:
wel1 year ago
5 0

Kirchhoff's loop rule is always true.

The foundation of circuit analysis is Kirchhoff's Laws for current and voltage. We have the fundamental set of tools required to begin evaluating circuits with these two principles, In an RLC circuit, the most fundamental elements of a resistor, inductor, and capacitor are connected across a voltage supply.

Learn more about Kirchhoff loop rule here-  

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Vikki [24]1 year ago
3 0

Only if all of the voltages are in phase with one another will the sum of the voltages around the circuit equal the applied voltage. However, in LCR circuits, the voltages across various components won't always be the same.

The phasor diagrams used throughout the chapter demonstrate that the voltages are added in a vector form rather than a scalar form. Although the voltages across various circuit elements are never concurrently at their highest values, Kirchhoff's loop rule is always true. Remember that an inductor has an emf that it can produce on its own and that the voltage across it is 90 degrees in front of the current in the circuit. Kirchhoff's Laws describe current in a node and voltage around a loop. These two laws are the foundation of advanced circuit analysis

Learn more about Voltages here-

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3 years ago
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Rufina [12.5K]
Remember that sound intensity decreases in inverse proportion to the distance squared. So, to solve this we are going to use the inverse square formula: \frac{I_{2} }{I_{1}}= (\frac{d{2} }{d_{1}})^2
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We can infer for our problem that I_{1}=270, d_{1}=1, and d_{2}=3. Lets replace those values in our formula to find I_{2}:
\frac{I_{2} }{I_{1}}= (\frac{d{2} }{d_{1}})^2
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\frac{I_{2} }{270} = \frac{1}{9}
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We can conclude that the intensity of the sound when is <span>3 m from the source is 30 dB.</span>
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Read 2 more answers
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