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Vera_Pavlovna [14]
2 years ago
11

What is an ideal gas

Physics
2 answers:
RSB [31]2 years ago
7 0

Answer:

Is a natural gas source manufactured

blsea [12.9K]2 years ago
4 0
Oxygen ??? Gas that u can see
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Which of the following best describes gravitational potential energy,
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The energy stored in an object when you lift it,
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A car is being lifted by a crane so that it moves upwards at a constant speed.
anygoal [31]

Answer:

Explanation:

Work done is defined as the product of force and the displacement in the direction of force.

W = F x d x Cos θ

Where, θ be the angle between force and the displacement.

The force of gravity acts downwards and the displacement is in upward, so the angle is 180. cos 180 = -1 , so the work done by the force of gravity is negative.

The force of rope acting in upwards direction and displacement also in upwards direction.

So, the work done is positive

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Crews at the International Space Station are researching the effects of the weightlessness of space on ________.
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6 0
3 years ago
Read 2 more answers
A basic physics question
Anna71 [15]
<h3>1)</h3>

No,kinetic energy cannot be negative since its given by KE=mv²,mass cannot be negative and the square of speed cannot b negative.

<h3>2)</h3>

Yes,any force opposing motion or displacement does negative work. They are often referred to as resistive forces (friction,air resistance,drag...)

<h3>3)</h3>

Nope it does not, it just forces the object to move in a circular path known as a centripetal force. It can accelerate an object by changing it's direction but not it's speed.

<h3>4)</h3>

No it cannot,If an object is sliding on the table (assuming it is not an incline), then most probably that normal force cancels out the weights effect or assuming there is an incline, it cancels the weight's y component.

<h3>5)</h3>

w = f.d.cos \alpha  = f.d.cos90 = 0

The work done is zero

<h3>6)</h3>

w = f.d.cos \theta = f.d.cos0 = f.d

The work is just the product of the magnitude of the force exerted and the displacement of the object.

<h3>7)</h3>

0 <  \theta < 90 \\ 1 < cos \theta < 0

<h3>Work is decreasing but positive</h3>

<h3>8)</h3>

\theta = 90 \\ cos \theta = cos90 = 0

<h3>Work is zero</h3>

<h3>9)</h3>

90 <  \theta < 180 \\ 0 < cos \theta <  - 1

<h3>Work is negative</h3>
3 0
2 years ago
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