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Levart [38]
3 years ago
13

" A bowl of soup at 200Á F. is placed in a room of constant temperature of 60Á F. The

Physics
1 answer:
Dahasolnce [82]3 years ago
7 0
<span>T(t)=60+140<span>e<span>−0.075t</span></span></span> <span>T(12)=60+140<span>e<span>−0.075∗12</span></span></span> <span>T(12)=60+140<span>e<span>−0.9</span></span></span> <span><span>T(12)=60+140(0.4065696597)
        =116.84
 So the temperature will be approximately 117 degrees</span></span>
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