The current flowing through a circuit can be measured by ?

A 1200-kg station wagon is moving along a straight highway at Another car, with mass 1800 kg and speed has its center of mass 40

taurus [48]

Answer:

Center of mass lies 24 m in front of center of mass of second wagon.

Explanation:

Suppose A 1200 kg station wagon is moving along a straight highway at 12.0 m/s. Another car with mass 1800 kg and speed 20.0 m/s.

Given that,

Mass of first wagon = 1200 kg

Mass of second wagon = 180 kg

Distance = 40 m

We need to calculate the position of the center of mass of the system

Using formula of center mass

$x_{cm}=\dfrac{m_{1}x_{1}+m_{2}x_{2}}{m_{1}+m_{2}}$

$x_{cm}=\dfrac{1200\times0+1800\times40}{1200+1800}$

$x_{cm}=24\ m$

Hence, Center of mass lies 24 m in front of center of mass of second wagon.

5 0

3 years ago

What is one result of a chemical change?

nordsb [41]

<span>One result of a chemical change is letter B: A new material is formed. Let us take for example on the paper being burned to ashes. There is a clear use of heat or thermal energy as heat is transferred from the medium to the paper, however, no energy is created, it only transformed to other energy. Materials may change but it could also happen to physical change like ice (which was in solid phase) turning or evaporating to water (liquid phase).</span>

7 0

3 years ago

An organ pipe open at both ends has a radius of 4.0 cm and a length of 6.0 m. what is the frequency (in hz) of the third harmoni

Marysya12 [62]

When air is blown into the open pipe,

L = $\frac{nλ}{2}$

where nis any integral number 1,2,3,4 etc. and λ is the wavelength of the oscillation

⇒λ= $\frac{2L} {n}$

Note here that n=1 is for fundamental, n=2 is first harmonic and so on..

⇒ third harmonic will be n=4

Given L=6m, n=4, solving for λ we get:

λ= $\frac{(2)*(6)}{4}$ =3m

Relationship of frequency(f), velocity of sound (c) and wavelength(λ) is:

c=f.λ Or f= $\frac{c}{λ}$

⇒f= $\frac{344}{3}$

≈115 Hz

8 0

4 years ago

Superman throws a 2400 n boulder at a villain. what horizontal force must superman apply to the boulder to give a horizontal acc

Ksenya-84 [330]

The boulder has a weight of W=2400 N. The weight of an object is the product between its mass m and the gravitational acceleration g:
$W=mg$
Rearranging the relationship, we can calculate the mass of the boulder:
$m= \frac{W}{g}= \frac{2400 N}{9.81 m/s^2}=244.6 kg$

We are told that Superman applies a horizontal force to this object, and as a result, the acceleration of the boulder is $a=12.0 m/s^2$ . We can find the force applied by using Netwon's second law of motion:
$F=ma=(244.6 kg)(12.0 m/s^2)=2935 N$

4 0

3 years ago

The blade of a windshield wiper moves through an angle of 90.08 in 0.40 s. The tip of the blade moves on the arc of a circle tha

oksian1 [2.3K]

Answer:

The centripetal acceleration is 6.95 m/s²

Explanation:

Given;

angular displacement of the blade, θ = 90.08⁰

duration of motion of the blade, t = 0.4 s

radius of the circle moved by the blade, r = 0.45 m

The angular speed of the blade in radian is calculated as;

$\omega = \frac{\theta}{t} \times \frac{\pi \ radian}{180^0} \\\\\omega = \frac{90.08 ^0}{0.4 \ s} \times \frac{\pi \ radian}{180^0} \\\\\omega = 3.93 \ rad/s$

The centripetal acceleration is calculated as;

a = ω²r

a = (3.93)² x 0.45

a = 6.95 m/s²

7 0

3 years ago