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n200080 [17]
4 years ago
6

Please help on this one

Physics
2 answers:
PolarNik [594]4 years ago
8 0

If the mass of both of the objects is doubled, then the force of gravity between them is quadrupled; and so on. Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces

s2008m [1.1K]4 years ago
5 0

The last choice on the list ... D ... is the correct one.


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Different wavelengths of light are seen as different. A. Atoms B. Sounds C. Colors D. Speeds
attashe74 [19]
Different wavelengths of light are seen as colors
7 0
3 years ago
John walked a distance of 900 meters in 10 minutes what was his average speed in kilomerters per hour
LuckyWell [14K]

Answer:

5.4

Explanation:

900/10=90 and 90(60)=5400 meters. 5400/100=5.4

3 0
3 years ago
A 10-g bullet moving horizontally with a speed of 1.8 km/s strikes and passes through a 5.0-kg block initially at rest on a hori
UNO [17]

Answer:

6.4 J

Explanation:

m = mass of the bullet = 10 g = 0.010 kg

v = initial velocity of bullet before collision = 1.8 km/s = 1800 m/s

v'  = final velocity of the bullet after collision = 1 km/s = 1000 m/s

M = mass of the block = 5 kg

V = initial velocity of block before collision = 0 m/s

V'  = final velocity of the block after collision = ?

Using conservation of momentum

mv + MV = mv' + MV'

(0.010) (1800) + (5) (0) = (0.010) (1000) + (5) V'

V' = 1.6 m/s

Kinetic energy of the block after the collision is given as

KE = (0.5) M V'²

KE = (0.5) (5) (1.6)²

KE = 6.4 J

4 0
4 years ago
A speaker fixed to a moving platform moves toward a wall, emitting a steady sound with a frequency of 205 Hz. A person on the pl
Arlecino [84]

Answer:

Explanation:

The question relates to Doppler effect and beat.

The observer is moving towards the reflected sound so apparent frequency will be increased

f = f₀ x (V + v₁) / (V - v₂)

f is apparent frequency , f₀ is real frequency , V is velocity of sound , v₁ is velocity of observer and v₂ is velocity of source . Here

v₁ = v₂ = vp as both observer and source have same velocity

f = f₀ x (V + v₁) / (V - v₂)

205 +5 = 205 x (344 +vp)/ ( 344 - vp)

1.0234 = (344 +vp)/ ( 344 - vp)

= 352 - 1.0234vp = 340+vp

12 / 2.0234vp

vp = 6 m /s approx.

6 0
3 years ago
An object with a weight of 20 kg will move _______ an object with a weight of 20 g if the same amount of force is placed on the
elena55 [62]
The answer should be D

7 0
3 years ago
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