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Alekssandra [29.7K]
2 years ago
12

How many grams of calcium metal is required to react with 7.75 g water to produce calcium hydroxide and hydrogen gas?

Physics
1 answer:
Gekata [30.6K]2 years ago
7 0

87.69 grams of calcium metal is required to react with 7.75 g water to produce calcium hydroxide and hydrogen gas.

Ca (OH)2+2H2 = CaH2 + 2H2O

Convert grams of hydrogen to moles of hydrogen.

H2 has a molar mass of 2.016 g/mol.

1 mol H2 x 8.400g H2

2.016g H2 equals 4.1667 mol H2

Calculate the moles of CaH2 using the molar ratio.

The molar ratio is 1 mol CaH2: 2 mol H2, according to the equation that is balanced.

2.0833 mol CaH2 = 4.1667 mol H2 1 mol CaH2 2 mol H2

grams of CaH2 to CaH2

CaH2 has a molar mass of 42.09 g/mol.

1.mol CaH2=87.69 g CaH2 2.0833mol CaH2=42.09 g CaH2

87.69 g CaH2 are required for the reaction.

Learn more about moles here-

brainly.com/question/26416088

#SPJ4

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Two circular coils are concentric and lie in the same plane. The inner coil contains 170 turns of wire, has a radius of 0.012 m,
GREYUIT [131]

Answer:

The current of the outer coil is  I_o   =   3.99 \ A

Explanation:

From the question we are told that

    The number of turns of the inner coil is  N_i  = 170 \ turn

    The radius of the  inner coil is R_i =  0.012 \ m

     The current of the inner coil is  I_i  =  6.2 \ A

      The number of turns of the outer coil is N_o  =  220 \ turns

      The radius of the  outer coil is R_o  =  0.02 0 \ m

       

Generally the net magnetic field is mathematically represented as

              B  =  \frac{N \ mu I }{ 2 * R  }

Now from told that the net magnetic field is common

So  

           \frac{N_i  \mu I_i} {2 * R _i} =  \frac{N_o  \mu I_o} {2 * R _o}

Here  \mu is the permeability of free space

making  I_o the subject

            I_o   =   \frac{ N_i  I_i *2 * R _o}{N_o  *2 * R _i}

substituting values

           I_o   =   \frac{ 170 *6.2 *2 * 0.020}{220   *2 * 0.012}

         I_o   =   3.99 \ A

5 0
3 years ago
Assume that the Deschutes River has straight and parallel banks and that the current is 0.75 m/s. Drifting down the river, you f
DedPeter [7]

Answer:

    d = 142.5 m

Explanation:

This is a vector exercise. Let's calculate how much the boat travels in the 40s

     d₀ = v_{b} t

    d₀ = 0.75 40

    d₀ = 30 m

Let's write the kinematic equations

Boat

     x = d₀  +  v_{b} t

     x = 0 +  v_{h} t

At the meeting point the coordinate is the same for both

    d₀  +  v_{b} t =  v_{h} t

    t ( v_{h} -  v_{b}) = d₀  

    t = d₀  / ( v_{b}-  v_{h})

The two go in the same direction therefore the speeds have the same sign

     t = 30 / (0.95-0.775)

     t = 150 s

The distance traveled by man is

     d =  v_{h} t

     d = 0.95 150

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3 0
4 years ago
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Answer:

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Answer:

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C(friction) = Frictional Force/Normal Force

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