Question

How many grams of calcium metal is required to react with 7.75 g water to produce calcium hydroxide and hydrogen gas?

Answer 1

87.69 grams of calcium metal is required to react with 7.75 g water to produce calcium hydroxide and hydrogen gas.

Ca (OH)2+2H2 = CaH2 + 2H2O

Convert grams of hydrogen to moles of hydrogen.

H2 has a molar mass of 2.016 g/mol.

1 mol H2 x 8.400g H2

2.016g H2 equals 4.1667 mol H2

Calculate the moles of CaH2 using the molar ratio.

The molar ratio is 1 mol CaH2: 2 mol H2, according to the equation that is balanced.

2.0833 mol CaH2 = 4.1667 mol H2 1 mol CaH2 2 mol H2

grams of CaH2 to CaH2

CaH2 has a molar mass of 42.09 g/mol.

1.mol CaH2=87.69 g CaH2 2.0833mol CaH2=42.09 g CaH2

87.69 g CaH2 are required for the reaction.

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