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Dominik [7]
3 years ago
15

Which of the following would be useful to show the growth rate of plants at varying temperatures? A. circle graph B. bar graph C

. line graph D. frequency table
Chemistry
2 answers:
miss Akunina [59]3 years ago
8 0

Line graph would be useful to show the growth rate of plants at varying temperatures.

Answer: Option C

<u>Explanation: </u>

Graphing are an important process in which scientists view data collected in a controlled experiment. The type of graph most commonly used in biology is a line graph. They are used to track changes in the short and long term periods.

For smaller changes, it is better to use line graphs than bar charts. It can also be supported to compare variations in more than a group in the same period. The commonly used line graphs are linear, polynomial, power, rational, quadratic, sinusoidal, logarithmic and exponential.

Pepsi [2]3 years ago
7 0

Answer: Im thinking the answer Is B) Bar graph?

Explanation:

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The most stable isotope would be lead-82.
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In molecular oxygen (O=O) which atom is partially positive?
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the oxygen atom

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Select the single best answer. Which mechanism properly shows the movement of electrons in the reaction? 2xsafari
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D

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5 0
3 years ago
If 2.60 g of NaBr are dissolved in enough water to make 160. mL of solution, what is the molar concentration of
navik [9.2K]

This problem has two parts; the first one asking for the concentration of NaBr given both its mass and volume and the second one asking for its volume given both mass and concentration. The answers turn out to be 0.158 M and 211 mL.

<h3>Molarity</h3>

In chemistry, the use of units of concentration depends on both the substances to analyze and their amounts. In such a way, for molarity, one needs the following relationship between the moles of solute and volume of solution:

M=\frac{n}{V}

Thus, for the first part of the problem we first calculate the moles in 2.60 g of NaBr via its molar mass:

2.60g*\frac{1mol}{102.89g} =0.0253mol

Next, we convert the 160. mL to L by dividing by 1000 in order to obtain 0.160 L to subsequently calculate the molarity:

M=\frac{0.0253mol}{0.160L}=0.158M

Next, since the moles remain the same and for the second part we are asked for the volume given the concentration, one can solve for the volume so as to obtain:

V=\frac{n}{M} =\frac{0.158M}{0.120mol/L}\\ \\V=0.211L

That in milliliters turns out to be:

V=0.211L*\frac{1000mL}{1L}=211mL

Learn more about molarity: brainly.com/question/10053901

6 0
2 years ago
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