Answer: B) Methyl alcohol requires less than half as much energy per kg to evaporate than water does
Explanation:
Latent heat of vaporization is the amount of heat required to convert 1 kilo gram of liquid into its vapor state without change in its temperature.
Heat of vaporization is more for water than for methyl alcohol which means more heat is required to convert from liquid to vapour form.
As the Heat of vaporization for methyl alcohol (1100) is almost half as that of Heat of vaporization for water (2257) , it means Methyl alcohol requires less than half as much energy per kg to evaporate than water does.
Explanation:
It is given that,
Initial vapor pressure, P₁ = 77.86 mm
Initial temperature, T₁ = 318.3 K
Final vapor pressure, P₂ = 161.3 mm
Initial temperature, T₂ = 340.7 K
We need to find its heat of vaporization. It can be calculated by using Clausius-Clapeyron equation.
So, the heat of vaporization of a substance is 29.31 kJ/mol. Hence, this is the required solution.
Fnet = (mass) (acceleration)
= 11 kg x 3.7m/s^2
= 41 N
