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zlopas [31]
3 years ago
6

An electron is carried from the positive terminal to the negative terminal of a 9 v battery. How much work is required in carryi

ng this electron?
Physics
1 answer:
shutvik [7]3 years ago
5 0

Answer:

The work required for the electron is 1.44x10^{-18} J

Explanation:

The work of the electron is calculated in the equation:

W= e * V

e= 1.6x10^{-19} C

C= Coulomb = s*A

V=  Volts = \frac{W}{A}

W= \frac{J}{s}

W= 1.6 x10^{-19}C *9 V\\W=1.44x10^{-18} C*V\\ W=1.44x10^{-18} s*A*\frac{W}{A} \\W=1.44x10^{-18} W*s\\W=1.44x10^{-18} \frac{J}{s}*s \\W=1.44x10^{-18} J\\

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Hopefully this help :)
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A vertical wire carries current in the upward direction. an electron is traveling parallel to the wire. what is the angle α betw
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An object with a higher temperature can have less thermal energy than an object
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2 years ago
A solar eclipse will occur Group of answer choices
myrzilka [38]

Answer:

3. at new Moon only when the Moon is on the ecliptic.

Explanation:

  • Solar eclipse is the condition when the moon comes in between the sun and the earth. In this condition the moon casts its shadow on the earth.
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7 0
3 years ago
Two particles, one with charge -5.45 × 10^-6 C and one with charge 4.39 × 10^-6 C, are 0.0209 meters apart. What is the magnitud
Levart [38]

Explanation:

Given that,

Charge 1, q_1=-5.45\times 10^{-6}\ C

Charge 2, q_2=4.39\times 10^{-6}\ C

Distance between charges, r = 0.0209 m

1. The electric force is given by :

F=k\dfrac{q_1q_2}{r^2}

F=9\times 10^9\times \dfrac{-5.45\times 10^{-6}\times 4.39\times 10^{-6}}{(0.0209)^2}

F = -492.95 N

2. Distance between two identical charges, r=0.0209\ m

Electric force is given by :

F=\dfrac{kq_3^2}{r^2}

q_3=\sqrt{\dfrac{Fr^2}{k}}

q_3=\sqrt{\dfrac{492.95\times (0.0209)^2}{9\times 10^9}}

q_3=4.89\times 10^{-6}\ C

Hence, this is the required solution.

3 0
2 years ago
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