Question

You kick a ball with a speed of 4 m/s at an angle of 10ﾟ. How far away does the ball land?

Answer 1

Answer: 0.55m



1. First find Vf
• 4 Sin(10)=0.7
•Vf= 0.7

2. Find time
•9.8=0.7/t
•9.8t=0.7
•t=0.07

3. Find distance
• 4 Cos(10)=d/0.14 < ————- double time
• d=0.55m

Answer 2

Answer:

The ball goes 0.555 meter  far away when kicked with a speed of 4 m/s at an angle of 10ﾟ.

Explanation :

From the given statements, we know  

Initial Velocity (u) = 4 m/s

Angle at which it is projected (θ) = 10 degree

Let acceleration due to gravity (g) = 9.8 m/$s^2$

Range = ?

Using the formula of Range, and substituting the values

Range= $\frac{\mathrm{u}^{2} \sin 2 \theta}{\mathrm{g}}$  

            = $\frac{4^{2} \sin 2 \times 10}{9.8}$

                = $\frac{16 \times 0.34}{9.8}$ = 0.555 m