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antiseptic1488 [7]
2 years ago
7

If you swim from one point at the edge of the pool to another, along a straight line, what is the longest distance d you can swi

m?
Physics
1 answer:
densk [106]2 years ago
4 0

The longest distance that a person can swim is 5.64 m.

<h3>What is the longest distance?</h3>

We know that the diameter of a circle is a line that is drawn from one point to another in the circle. Now we are told that the pool is circular in nature. That implies that the longest that a person can swim could be obtained form the diameter of the circle.

Given that;

A =  πr^2

A = area of teh circular pool

r  = radius of the pool

r = √A/ π

r = √25/3.142

r = 2.82m

Diameter of the circular pool = 2 r = 2 (2.82 cm) = 5.64 m

Learn more about circle:brainly.com/question/11833983

#SPJ1

Missing parts;

An ad for an above-ground pool states that it is 25 m2. From the ad, you can tell that the pool is a circle. If you swim from one point at the edge of the pool to another, along a straight line, what is the longest distance d you can swim? Express your answer in three significant figures.

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adelina 88 [10]

Answer:

The length of the wire is 579 m

Explanation:

Given;

current on the wire, I =  11.3-mA

magnetic field of the wire, B = (16.2i + 2.4 ĵ) T

Magnitude of force experience by the wire, F = 15.7 N

Magnitude of force experience by  current carrying wire at a given a magnetic field strength is calculated as;

F = BILsinθ

Where;

B is magnitude of magnetic field

F is the force on the wire

L is length of the wire

θ is direction of the magnetic field

B = \sqrt{16.2^2 +2.4^2} = \sqrt{268.2} = 16.377 \ T

tan \theta = \frac{2.4}{16.2} \\\\tan \theta =  0.1482\\\\\theta = tan^{-1}(0.1482) \\\\\theta = 8.43^o

Length of the wire is calculated as;

L = \frac{F}{BIsin \theta} = \frac{15.7}{16.377*11.3*10^{-3}*sin(8.43)} = 578.9 \ m

Therefore, the length of the wire is 579 m

5 0
3 years ago
Determine the gravitational potential energy, in kJ, of 3 m3 of liquid water at an elevation of 40 m above the surface of Earth.
melomori [17]

Explanation:

We will calculate the gravitational potential energy as follows.

                 P.E_{1} = mgz_{1}

       P.E_{1} = (\rho V)gz_{1}    

                    = 1000 kg/m^{3} \times 3 m^{3} \times 9.7 \times 40 m

                    = 1164000 J

or,                = 1164 kJ         (as 1 kJ = 1000 J)

Now, we will calculate the change in potential energy as follows.

             \Delta P.E = mg(z_{2} - z_{1})

                         = \rho \times V \times g (z_{2} - z_{1})

                         = 1000 \times 3 \times 9.7 (10 - 40)m

                         = -873000 J

or,                      = -873 kJ

Thus, we can conclude that change in  gravitational potential energy is -873 kJ.

4 0
3 years ago
You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics
olga nikolaevna [1]

Answer:112.82 m/s

Explanation:

Given

range of arrow=68 m

Angle=3^{\circ}

as the arrow travels it acquire a vertical velocity v_y

v_y=u+at

v_y=0+9.81\times t-------1

Range is given by

R=ut

where u=initial velocity

68=u\times t

t=\frac{68}{u}

substitute the value of t in eqn 1

v_y=9.81\times \frac{68}{u}

v_y\times u=9.81\times 68=667.08--------2

and tan(3)=\frac{v_y}{u}

v_y=utan(3)=0.0524u

substitute it in 2

0.0524 u^2=667.08

u^2=12,728.644

u=112.82 m/s

6 0
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AlexFokin [52]
The potential energy is stored in the chemical bonds of the food. When those bonds break up during the metabolic processes, the energy is released. After that, that energy is stored in the Adenosine Triphosphate bonds aka ATP. The simplest way to think is to think of food as the tightly bound atoms. When the chemical bonds between those atoms break, the stored energy in that food is released. 
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The Earth's _____
fenix001 [56]

Answer:

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Explanation:

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