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Ulleksa [173]
2 years ago
11

. white light (containing all visible colors) passes through a gas that absorbs some of the light. the spectrum is then analyzed

. how could that spectrum best be described?
Physics
1 answer:
irinina [24]2 years ago
5 0

White light (containing all visible colors) passes through a gas that absorbs some of the light, the spectrum is then analyzed.

That spectrum best be described as a spectrum that is continuous except for few black lines.

<h3>What is spectrum?</h3>
  • The variation in light's intensity with frequency or wavelength.
  • A spectroscope is a device created for visual spectral observation, while a spectrograph is a device that captures or maps spectra.
  • The sun's spectrum of colors, the rainbow, and a molecule's infrared absorption wavelengths are a few examples of spectra.
  • Continuous, emission, and absorption spectra are the many types.
  • A conceptual tool called the Spectrum is used to map and organize the electromagnetic wave's physical events.
  • The electromagnetic spectrum is the collection of all conceivable radio frequencies at which these waves can flow through space.

Learn more about spectrum here:

brainly.com/question/3997802

#SPJ4

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A 6.00-mH solenoid is connected in series with a 5.0-μF capacitor and an AC source. The solenoid has internal resistance 3.0 Ω w
son4ous [18]

Answer:

5773.50269 Hz

23 A

Explanation:

L = Inductance = 6 mH

C = Capacitance = 5 μF

R = Resistance = 3 Ω

\epsilon = Maximum emf = 69 V

Resonant angular frequency is given by

\omega=\dfrac{1}{\sqrt{LC}}\\\Rightarrow \omega=\dfrac{1}{\sqrt{6\times 10^{-3}\times 5\times 10^{-6}}}\\\Rightarrow \omega=5773.50269\ Hz

The resonant angular frequency is 5773.50269 Hz

Current is given by

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7 0
3 years ago
A 3.0-kg block starts at rest at the top of a 37° incline, which is 5.0 m long. Its speed when it reaches the bottom is 2.0 m/s.
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W_{x} = horizontal component of the weight = mgsinФ

W_{y} = vertical component of weight = mgcosФ

Due to the way the object is positioned, the horizontal component of force will accelerate the object thus acting as an applied force.

by using newton's law of motion, we have that

mgsinФ - f_{r} = ma

where m = mass of object=5kg

a = acceleration= unknown

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g = acceleration due to gravity = 9.8m/s^{2}

f_{r} = frictional force = unknown

we need to first get the acceleration before the frictional force which is gotten by using the equation below

v^{2} = u^{2} + 2aS

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u = initial velocity = 0m/s (because the object started from rest)

a= unknown

S= distance covered = length of plane = 5m

2^{2} = 0^{2} + 2*a*5\\\\4= 10 *a\\\\a = \frac{4}{10} \\a = 0.4m/s^{2}

we slot in a into the equation below to get frictional force

mgsinФ - f_{r} = ma

3 * 9.8 * sin 37 - f_{r} = 3* 0.4

17.9633 - f_{r} =  1.2

f_{r} = 17.9633 - 1.2

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