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eimsori [14]
3 years ago
14

Calculate the mass percent of oxygen in KMnO4.

Chemistry
1 answer:
ASHA 777 [7]3 years ago
4 0

Answer: 40.496%

Hope this helps! (:

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How many kilojoules of heat are released when 32.0 g of NaOH are dissolved in water? (The molar heat of solution of NaOH is –445
Katen [24]
The energy release when dissolving 1 mol of NaOH in water is 445.1 kJ
the mass of NaOH to be dissolved is 32.0 g
The number of NaOH moles in 32.0 g - 32.0 g / 40 g/mol =  0.8 mol
the energy released whilst dissolving 1 mol of NaOH - 445.1 kJ
when dissolving 0.8 mol - the energy released is 445.1 kJ/mol x 0.8 mol
therefore heat released is - 356.08 kJ
answer is -356.08 kJ
6 0
3 years ago
Read 2 more answers
If a pea plant is tall, and tallness in pea plants is dominant over shortness, what is the phenotype of the pea plant?
Firlakuza [10]

Answer:

The height of the plant is controlled by two alleles - the dominant 'T' for tallness and recessive 't' for shortness of the plant. The dominant allele represses the expression of the recessive allele. The recessive allele is expressed only in the homozygous state (tt)

6 0
2 years ago
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Is this chemical equation balanced?
cluponka [151]

Answer:

Yes

Explanation:

5 0
3 years ago
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The following unbalanced equation illustrates the overall reaction by which the body utilizes glucose to produce energy: C6H12O6
s344n2d4d5 [400]

Answer:

the conversion factor is f= 6  mol of glucose/ mol of CO2

Explanation:

First we need to balance the equation:

C6H12O6(s) + O2(g) → CO2(g) + H2O(l) (unbalanced)

C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(l) (balanced)

the conversion factor that allows to calculate the number of moles of CO2 based on moles of glucose is:

f = stoichiometric coefficient of CO2 in balanced reaction / stoichiometric coefficient of glucose in balanced reaction

f = 6 moles of CO2 / 1 mol of glucose = 6  mol of glucose/ mol of CO2

f = 6 mol of CO2/ mol of glucose

for example, for 2 moles of glucose the number of moles of CO2 produced are

n CO2 = f * n gluc = 6 moles of CO2/mol of glucose * 2 moles of glucose= 12 moles of CO2

3 0
3 years ago
1. A student attempts to make a saline solution by adding salt to water. How much water did
dexar [7]

111.1 mL of water

Explanation:

Weight per volume concentration (w/v %) is defined as

weight per volume concentration = (mass of solute (g) / volume of solution (mL)) × 100

volume of solution = (mass of solute × 100) / weight per volume concentration

volume of solution = (1 × 100) / 0.9 = 111.1 mL

volume of water = volume of solution = 111.1 mL

Learn more about:

weight per volume concentration

brainly.com/question/12721794

#learnwithBrainly

8 0
3 years ago
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