<h3><u>Answer</u>;</h3>
a. 3 molecules 3 carbon
b. 6 molecules 18 carbon
c. 6 molecules 18 carbon
d. 5 molecules 15 carbon
e. 3 molecules 15 carbon
f. 3 molecules 15 carbon
<h3><u>Explanation</u>;</h3>
- In the Calvin cycle, carbon atoms from CO2 are ncorporated into organic molecules and then used to build three-carbon sugars, a process that is fueled by, and dependent on, ATP and NADPH from the light reactions.
- Calvin cycle take place in the stroma. Reactions of Calvin cycle are divided into three main stages: carbon fixation, reduction, and regeneration of the starting molecule.
- During carbon fixation, a CO2 molecule combines with a five carbon acceptor molecule ribulose-1,5-bisphosphate. The result is a six carbon compound that splits to two three carbon compound, 3-PGA.
- During reduction; ATP and NADPH are used to convert the 3-PGA molecules into molecules of a three-carbon sugar, glyceraldehyde-3-phosphate.
- Finally during regeneration, some G3P molecules are used to make glucose while others are recycled to regenerate RuBP acceptor.
0.60759572 gal is the volume of acid in gallons in a sample of hydraulic acid .
<h3>What do mean by the term "gallons" ?</h3>
The gallon is a unit of measurement for volume and fluid capacity in both the US units and the British imperial systems of measurement.
In SI base units, 1 Gal is equal to 0.01 m/s²
Since ,
1 L, l = 0.2641720524 gal
now, volume of acid in gallons is given by -
2.3 L, l = 2.3 × 0.2641720524 gal
=0.60759572 gal
Hence , 0.60759572 gal is the volume of acid in gallons in a sample of hydraulic acid .
Learn more about gallon ,here:
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n = PV/RT
p = 1.6 atm
v = 12.7L
R = 0.0821
T = 24°C which is equivalent to 297.15 degrees k
n = (16 × 12.7) / (0.0821 × 297.15)
n = 20.32 / 24.39
n = 0.83 mol
C = 12.90
H = 1.0079
C2 = 12.010 × 2 = 24.02
H6 = 1.0079 × 6 = 6.0474
C2H6 = 30.0674
Ethane times n which is 30.0674 × 0.83mol
= 24.95 grams of C2H6. Which is Ethane.
The value of Kc for the equilibrium is 0.150 mole² / litre ²
<u>Explanation:</u>
<u>Given:</u>
An equilibrium mixture in an 1.00 L vessel contains 5.30 moles of
Mg(OH )₂ 0.800 moles of Mg²⁺ and 0.0010 moles OH₋
We have to find the value of Kc
- Step 1: Find the equilibrium Concentration.
- Step 2: Substitute the values in the equation.
- Step 3: Find the value of Kc.
- I have attached the document for the detailed explanation
The value of Kc for the equilibrium is 0.150 mole² / litre ²
