Answer:
1299 N/m²
Explanation:
Applying,
P = ρgh............... Equation 1
Where P = pressure of water at the bottom of the container, ρ = density of water, h = height of water in the container, g = acceleration due to gravity.
but,
V = πr²h............ Equation 2
Where V = volume of water, r = radius of the container
make h the subject of the equation
h = V/πr².................. Equation 3
From the question,
Given: V = 200 liters, = 200000 cm³, r = 70 cm
Constant: π = 22/7
Substitute these values into equation 3
h = 200000/[(22/7)(70²)]
h = 12.99 cm
h = 0.1299 m
Also given
Constant: g = 10 m/s², ρ = 1000 kg/m³
Substitute these values into equation 1
P = 0.1299(10)(1000)
p = 1299 N/m²
Answer:
Avg.velocity=(Δy/ Δt) =(net displacement/ total time for journey)
Δy = 0
Δt = t
so avg. velocity = 0/t =0
Avg. speed =(total distance traveled/ total time for journey)
total distance = up +down = Ymax+Ymax= 2 Ymax
total time = t
avg. speed = 2 Ymax/t
Explanation:
Since there is no net displacement from the original position,velocity is zero. Claudia is right!
while it covered some distance in time t so its speed is not as qouted by Hossien
Given Information:
Radius = r₁ = 150 m
Radius = r₂ = 73 m
Maximum speed = v₁ = 28.0 m/s
Required Information:
Maximum speed = v₂ = ?
Answer:
Maximum speed v₂ = 19.53 m/s
Explanation:
The maximum acceleration of the truck is
a = v²₁/r₁
a = 28²/150
a = 5.226 m/s²
Now if we change the radius to r₂ = 73 m
Then the maximum speed of the truck is
v₂ = √a*r₂
v₂ = √5.226*73
v₂ = 19.53 m/s
So the speed of the truck is decreased when the radius of curve is decreased.
The motion of particles to one side of the rest position will be the same as the motion of the other side of the rest position in a wave motion. because in a wave motion or wave function, it symmetrical. meaning the motion on the other side will be identical to the other side of the rest position
