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1 year ago

Determine the electron-group arrangement, molecular shape, and ideal bond angle(s) for each of the following:

1 answer:

6 0

The electron-group arrangement of CO₃²⁻ is trigonal planar. The molecular shape is trigonal planar, and the ideal bond angle(s) is CO₃²⁻ is 120°

<h3>What is the molecular geometry of a compound?</h3>

The position of the compound's electrons and nuclei can be seen in the molecular geometry. It demonstrates how the form of the complex is created by the interaction of electrons and nuclei.

Here, according to the VSEPR theory, the shape of the carbonate ion is trigonal planar. The carbon will be in the center.

Thus, the electron-group arrangement and the shape of the carbonate ion are trigonal planar. The bond angle will be 120°.

To learn more about molecular geometry, refer to the link:

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Give three examples,from the lab where potential energy was converted to kinetic energy?

creativ13 [48]

Answer:

*a car geared neutral that is at a stop. two men start pushing it

*tire physical therapy. trie is at rest until you come up to the tire and flip it

*pushing a wheel barrel

Explanation:

everthing has to be at a complete stop then through energy be moved

7 0

3 years ago

What is the velocity of a 485 kg elevator that has 5900 J of energy?

Ganezh [65]

The velocity of a 485 kg elevator that has 5900 J of energy is 108.6 m/s

<h3>What is the velocity of the elevator?</h3>

A moving elevator possesses kinetic energy due to its motion.

The velocity of the elevator is calculated from the formula of kinetic energy.

The kinetic energy formula is : Kinetic energy = ¹/₂mv₂

The velocity, v = √2KE/m

v = √(2 * 5900/485)

v = 108.6 m/s

In conclusion, the velocity of the elevator is calculated from the kinetic energy and mass of the elevator.

Learn more about velocity and kinetic energy at: brainly.com/question/25959744

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7 0

1 year ago

The force between two atoms is the result of _____________________ repulsion, nucleus-nucleus ________________, and nucleus-elec

Elanso [62]

Answer:

<h2>(1). electron electron repulsion</h2><h2>(2). repulsion </h2><h2>(3). attraction </h2><h2>(4). maximum attraction </h2><h2>(5). attractive </h2><h2>(6). repulsive </h2><h2>(7). maximum attraction </h2><h2>(8). molecule </h2>

Explanation:

The same charges repel each other while opposite charges attract each other. During electron-electron interaction repulsion take palace because the electron has negative charges. Nucleus has positive charges so the interaction between two nucleus results in the form of repulsion. When interaction takes place between nucleus and electron then attraction takes place between nucleus and electrons due to opposite charges.

The formation of a bond that takes place due to the sharing of the electrons is known as a covalent bond and thus the covalent molecule is formed.

4 0

3 years ago

Use the following information S(s)+O2(g)→SO2(g), ΔH∘ = -296.8kJ SO2(g)+12O2(g)→SO3(g) , ΔH∘ = -98.9kJ to calculate ΔH∘f for H2SO

Irina-Kira [14]

Answer : The enthalpy of formation of $H_2SO_4$ is, -812.4 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation of $H_2SO_4$ will be,

$S+H_2+2O_2\rightarrow H_2SO_4$ $\Delta H_{formation}=?$