Ba(OH)2 is an basic solution. It has more OH- ions than H+ ions. pOH should be calculated to find out its pH
The reaction is
Ba(OH)2 ⇒ Ba2+ (aq) + 2 OH-(aq)
One mole barium hydroxide releases 2 moles hydroxide ions.
Use that ratio to calculate molarity (M) of OH- ions [OH-]. The ratio is 1:2.
0.10 M Ba(OH)2 release 2*0.10 M= 0.02 M OH- ions
[OH-]= 0.02
pOH= - log [OH-] = - log 0.02 = 1.7
Thats not the answer! We found pOH of the solution before titration.
pH and pOH relationship is shown by formula of pH+pOH= 14
pH= 14-pOH
pH= 14-1.7= 12.3
Answer:
The answer to your question is: Flask X
Explanation:
Data
Flask X Flask B
Molar mass 30 g 60 g
mass 1.2g 1.2 g
Pressure 1 atm 0.5 atm
Formula PV = nRT
In the formula, we can notice that the number of moles (n)
is directly proportional to the pressure.
Then, let's calculate the number of moles
flask X flask Y
30 g --------------- 1 mol 60 g -------------- 1 mol
1.2 g ---------------- x 1.2 g ------------- x
x = (1.2 x 1) / 30 x = (1.2 x 1) / 60
x = 0.04 mol x = 0.02 mol
From the results, we conclude that the flask with the gas of molar mass 30g is the flask with pressure of 1 atm, because the higher the number of moles, the higher the pressure.