if glucose labelled at the c-1 position with 14c passes through glycolysis, on which carbon of pyruvate will the radiolabel be f
1 answer:
Carbon of pyruvate will be found on 3.
Catabolism is the set of metabolic pathways that breaks down large molecules, in this example glucose, into smaller units.
Glycolysis is metabolic 10 steps process in which sugar glucose (six carbon atoms) is break into two molecules of pyruvate (three carbon atoms). In this process, energy is released. Also, ATP, NADH, and water are products of this metabolic pathway.
During the glycolysis carbon atoms are oxidized.
Carbon-1 position in glucose is changed to carbon-3 position in pyruvate (see picture below).
In eukaryotes, glycolysis takes place in the cytosol of the cell.
More about glycolysis: brainly.com/question/737320
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Answer:
4.08 × 10⁻³
Explanation:
Step 1: Write the balanced reaction at equilibrium
NH₄I(s) ⇄ NH₃(g) + HI(g)
Step 2: Calculate the equilibrium constant
The equilibrium constant (K) is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. Only gases and aqueous species are included.