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1 year ago

14

When a reaction mixture reaches chemical equilibrium, ____. please choose the correct answer from the following choices, and the

n select the submit answer button. answer choices

1 answer:

grin007 [14]1 year ago

8 0

The rate of the forward an reverse reaction are equal

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Match each body system with its main organ.

olya-2409 [2.1K]

Answer:

it's in the explanation

Explanation:

Lungs- Respiratory

Heart- Circulatory

Brain- Nervous

Stomach- Digestive

Bladder- Excretory

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3 years ago

Consider the unbalanced equation for the oxidation of aluminum. _Al + _O2 Right arrow. _Al2O3 Which sequence of coefficients sho

inysia [295]

Answer:

4,3,2

Explanation:

if you balance a chemical equation that is the correct coefficients to be placed in the blank space

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3 years ago

Read 2 more answers

If a pork roast must absorb kJ to fully cook, and if only 10% of the heat produced by the barbecue is actually absorbed by the r

kolezko [41]

Answer:

1,033.56 grams of carbon dioxide was emitted into the atmosphere.

Explanation:

$C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g),\Delta H_{rxn}=-2044 kJ/mol (assuming)$

Energy absorbed by pork,E = $1.6\times 10^3 kJ$ (assuming)

Total energy produced by barbecue = Q

Percentage of energy absorbed by pork = 10%

$10\%=\frac{E}{Q}\times 100$

$Q=\frac{E}{10}\times 100=\frac{1.6\times 10^3 kJ}{10}\times 100=1.6\times 10^4 kJ$

Since, it is a energy produced in order to indicate the direction of heat produced we will use negative sign.

Q = $-1.6\times 10^4 kJ$

Moles of propane burnt to produce Q energy =n

$n\times \Delta H_{rxn}=Q$

$n=\frac{Q}{\Delta H_{rxn}}=\frac{-1.6\times 10^4 kJ}{-2044 kJ/mol}=7.83 mol$

According to reaction , 1 mol of propane gives 3 moles of carbon dioxide. then 7.83 moles of will give:

$\frac{1}{3}\times 7.83 mol=23.49 mol$ carbon dioxide gas.

Mass of 23.49 moles of carbon dioxide gas:

23.49 mol × 44 g/mol =1,033.56 g

1,033.56 grams of carbon dioxide was emitted into the atmosphere.

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3 years ago

What is the ph of an acetic acid solution if 10 drops are titrated with 70 drops of a 0.65 m koh solution? (ka for acetic acid =

laiz [17]

<span>What is the ph of an acetic acid solution if 10 drops are titrated with 70 drops of a 0.65 m koh solution? (ka for acetic acid = 1.8 x 10-5)?

[KOH] = 0.65 M
[OH] = 0.65 M
</span>Dilute your mom
<span>[OH]Dil= 0.65 M * 70/80 = 0.56875 M

pH = 5.4
</span>

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3 years ago

For sediment to be transformed into rock, which set of procces must take place?

Burka [1]

Answer:

compaction and cementation.

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3 years ago