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Eva8 [605]
3 years ago
11

2 AIPO4 + 3 BaCl2 --> 2 AICIz + 1 Baz(PO4)2

Chemistry
1 answer:
givi [52]3 years ago
3 0

Answer:

12.3 moles of AlCl_{3} are produced by reacting 18.4 moles of BaCl_{2} .

Explanation:

Balanced reaction: 2AlPO_{4}+3BaCl_{2}\rightarrow 2AlCl_{3}+Ba_{3}(PO_{4})_{2}

According to balanced equation:

3 molecules of BaCl_{2} produce 2 molecules of AlCl_{3}

So 3N_{A} molecules of BaCl_{2} produce 2N_{A}  molecules of AlCl_{3} (N_{A} is avogadro number).

We know 1 mol of molecule = N_{A} number of molecules.

So 3 moles of BaCl_{2} produce 2 moles of AlCl_{3}.

Hence 18.4 moles of BaCl_{2} produce (\frac{2}{3}\times 18.4) moles of AlCl_{3} or 12.3 moles of AlCl_{3} .

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Initial              0.0375       0        0
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Equilibrium    0.0375-x     x        x

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