Question

2 AIPO4 + 3 BaCl2 --> 2 AICIz + 1 Baz(PO4)2

Answer 1

Answer:

12.3 moles of $AlCl_{3}$ are produced by reacting 18.4 moles of $BaCl_{2}$ .

Explanation:

Balanced reaction: $2AlPO_{4}+3BaCl_{2}\rightarrow 2AlCl_{3}+Ba_{3}(PO_{4})_{2}$

According to balanced equation:

3 molecules of $BaCl_{2}$ produce 2 molecules of $AlCl_{3}$

So $3N_{A}$ molecules of $BaCl_{2}$ produce $2N_{A}$  molecules of $AlCl_{3}$ ($N_{A}$ is avogadro number).

We know 1 mol of molecule = $N_{A}$ number of molecules.

So 3 moles of $BaCl_{2}$ produce 2 moles of $AlCl_{3}$.

Hence 18.4 moles of $BaCl_{2}$ produce $(\frac{2}{3}\times 18.4)$ moles of $AlCl_{3}$ or 12.3 moles of $AlCl_{3}$ .