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Marina86 [1]
1 year ago
9

Why does hitting a magnet with a hammer cause the magnetism to be reduced?

Physics
1 answer:
Katarina [22]1 year ago
8 0

Hitting a magnet with a hammer cause the magnetism to be Physical disruption and vibration damage the material's order, demagnetizing it.

<h3>Explanation:</h3>

There are numerous methods for demagnetizing a magnet.

A magnet, as we know, has magnetic moments, which are the arrangements of molecules in a specific direction.

The hammer causes the magnetic poles of the magnet to point in opposite directions, causing the magnet to bend.

When we repeatedly hammer on a magnet, the magnetic dipoles inside the magnet are released from their ordered configuration.

Magnetism is known to be caused by the presence of magnetic moments.

As a result, when we hammer it, the dipoles are perturbed, lose their orientation, and magnetic moments cease to exist. As a result, the magnet will become demagnetized.

<h3>What is Magnetism?</h3>

The force that magnets use to either attract or repel one another is known as magnetism.

Electric charges in motion are what generate magnetism. Every substance is made of small particles known as atoms.

Electrons, which are charged particles, are found in every atom. Electrons spin like tops around an atom's nucleus, or center. Their mobility causes an electric current to flow, causing each electron to act as a miniature magnet.

Another strongly magnetic substance must enter the magnetic field of an existing magnet in order to be magnetized. A magnet's magnetic field is the area of magnetic force that surrounds it.

An electric current can magnetize some compounds.

To learn more about magnetism, visit:

brainly.com/question/13026686

#SPJ4

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Answer:

v = 8.09   m/s

Explanation:

For this exercise we use that the work done by the friction force plus the potential energy equals the change in the body's energy.

Let's calculate the energy

       

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         Em_f = K = ½ m v²

The work of the friction force is

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to find the friction force let's use Newton's second law

Axis y

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        N = W_y

X axis

        Wₓ - fr = ma

let's use trigonometry

        sin  θ = y / L

         sin θ = 11/110 = 0.1

         θ = sin⁻¹  0.1

          θ = 5.74º

         sin 5.74 = Wₓ / W

         cos 5.74 = W_y / W

         Wₓ = W sin 5.74

         W_y = W cos 5.74

the formula for the friction force is

         fr = μ N

         fr = μ W cos θ

Work is friction force is

         W_fr = - μ W L cos θ  

Let's use the relationship of work with energy

        W + ΔU = ΔK

         -μ mg L cos 5.74 + (mgh - 0) = 0  - ½ m v²

        v² = - 2 μ g L cos 5.74 +2 (gh)

        v² = 2gh - 2 μ gL cos 5.74

let's calculate

        v² = 2 9.8 11 - 2 0.07 9.8 110 cos 5.74

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        v = √65.44

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f = v / λ = 340 / 3.4 = 100 Hz

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Frequency of beat, n = f' - f = 103.03 - 100 = 3.03 Hz

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Answer:

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