Answer:
3.60 mol CO₂
Explanation:
Balanced chemical reaction:
2CO + O₂ ⇒ 2CO₂
The molar ratio between CO₂ and CO is 1:1
2CO₂/2CO = CO₂/CO
Thus, the moles of CO₂ produced from 3.60 moles of CO is 3.60 moles:
(3.60 mol CO)(CO₂/CO) = 3.60 mol CO₂
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Answer:
Pb⁺²(aq) + CO₃⁻²(aq) → PbCO₃ (s)
In net ionic equation we cancel the ions that have equal moles on both sides so Na⁺¹ and NO₃⁻¹ have equal moles on both sides so we canceled them.
Explanation:
Net ionic equation:
In net ionic equation we only write the ions that are involved in reaction. If the system have same moles of ions in initial and final stages we cancel them as they have the same amount and are present in ionic form in the reaction medium. To formulate an ionic equation we just cancel the ions which have the same moles in initial and final stages.
Chemical equation:
Pb(NO₃)₂ (aq) + Na₂CO₃(aq) → PbCO₃ (s) + NaNO₃ (aq)
Balanced chemical equation:
In a balanced chemical equation we write the reactants and products in molecular form with number of moles.
Pb(NO₃)₂ (aq) + Na₂CO₃(aq) → PbCO₃ (s) + 2NaNO₃ (aq)
Ionic equation:
In ionic equation we write the equation in ionic form. It involves all the ions which will produce when we add any ionic compound in reaction medium.
Pb⁺² +2NO₃⁻¹ + CO₃⁻² + 2Na⁺¹ → PbCO3 (s) + 2NO₃⁻¹ (aq) + 2Na⁺¹ (aq)
Net ionic equation
In net ionic equation we cancel the ions that have equal moles on both sides. As we can see in the above ionic equation that Na⁺¹ and NO₃⁻¹ have equal moles on both sides so we canceled them.
Pb⁺²(aq) + CO₃⁻²(aq) → PbCO₃ (s)
1) Recording the change in pressure when heating an inflated tire
Explanation:
This happens because with an increase in temperatures, the kinetic energy of the gas in the tire increases. The increase in kinetic energy means the molecules move more rapidly. There is an increased rate of collisions between the gas molecules, and increased energy of the collisions, and between the gas molecules and inner walls of the tire hence the increased pressure. Pressure and temperatures and directly proportional s long as the volume of the gas is kept constant.
Answer:
RxN: Na₂CO₃ (aq) + 2HCl (aq) → 2NaCl (aq) + H₂CO₃ (aq)
NIE: n/a
Explanation:
Step 1: Predict (Double Replacement)
Na₂CO₃ (aq) + HCl (aq) → NaCl (aq) + H₂CO₃ (aq)
Step 2: Balance
Na₂CO₃ (aq) + 2HCl (aq) → 2NaCl (aq) + H₂CO₃ (aq)
Step 3: Write Total Ionic Equation
2Na⁺ (aq) + CO₃²⁻ (aq) + 2H⁺ (aq) + 2Cl⁻ (aq) → 2Na⁺ (aq) + 2Cl⁻ (aq) + 2H⁺ (aq) + CO₃²⁻ (aq)
Step 4: Remove Spectator Ions
- Na⁺
- CO₃²⁻
- H⁺
- Cl⁻
Step 5: Write Net Ionic Equation
None.