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seraphim [82]
1 year ago
5

if your vehicle begins to slide or skid in the rear, you should? group of answer choices press the gas pedal and speed up. steer

away from the direction of the rear skid. steer in the direction that the rear is sliding to. hit the breaks and hold on.
Physics
1 answer:
MariettaO [177]1 year ago
7 0

if your vehicle begins to slide or skid in the rear, you should steer in the direction that the rear is sliding to.

<h3>What should you do if the rear end of the vehicle starts to slide or skid?</h3>

In the case above, a person need to Look as well as steer in the direction that the person want the front of the vehicle to go.

Note that  in the case above;

Do stay way from  the brake pedal and never apply the brakes.

  • Steer in the the same direction as the rear of the vehicle that is known to be  sliding. This will give room for the vehicle to go straight instead of going sideways.
  • Then make sure to get ready to steer in the opposite direction if the vehicle is one that begins swerving in the other direction.

Therefore, if your vehicle begins to slide or skid in the rear, you should steer in the direction that the rear is sliding to.

Learn more about slide or skid from

brainly.com/question/2148046

#SPJ1

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3-6 seconds time interval is the object slowing down.

The correct option is C.

<h3>What is a time interval?</h3>

The time interval is the span of time among two specified times. To put it another way, it is the amount of time that has passed between the event's start and finish.

<h3>What are different time intervals?</h3>

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The complete question is -

During which time interval is the object slowing down ?

a- 8-10 seconds

b- 6-8 seconds

c- 3-6 seconds

d- 0-3 seconds

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1 year ago
A uniform rod of length L, mass M, is suspended by two thin strings. Which of the following statements is true
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Answer:

(d) not enough info

Explanation:

because it doesn't specify where the strings are attached

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6 0
3 years ago
A book is resting on the table. Forces are exerted _____.
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3 years ago
Read 2 more answers
Willie, in a 100.0 m race, initially accelerates uniformly from rest at 2.00 m/s2 until reaching his top speed of 12.0 m/s. He m
Oduvanchick [21]

Answer:

The total time for the race is 11.6 seconds

Explanation:

The parameters given are;

Total distance ran by Willie = 100.0 m

Initial acceleration = 2.00m/s²

Top speed reached with initial acceleration = 12.0 m/s

Point where Willie start to fade and decelerate = 16.0 m from the finish line

Speed with which Willie crosses the finish line = 8.00 m/s

The time and distance covered with the initial acceleration are found using the following equations of motion;

v = u₀ + a·t

v² = u₀² + 2·a·s

Where:

v = Final velocity reached with the initial acceleration = 12.0 m/s

u₀ = Initial velocity at the start of the race = 0 m/s

t = Time during acceleration

a = Initial acceleration = 2.00 m/s²

s = Distance covered during the period of initial acceleration

From, v = u₀ + a·t, we have;

12 = 0 + 2×t

t = 12/2 = 6 seconds

From, v² = u₀² + 2·a·s, we have;

12² = 0² + 2×2×s

144 = 4×s

s = 144/4 =36 meters

Given that the Willie maintained the top speed of 12.0 m/s until he was 16.0 m from the finish line, we have;

Distance covered at top speed = 100 - 36 - 16 = 48 meters

Time, t_t of running at top speed = Distance/velocity = 48/12 = 4 seconds

The deceleration from top speed to crossing the line is found as follows;

v₁² = u₁² + 2·a₁·s₁

Where:

u₁ = v = 12 m/s

v₁ = The speed with which Willie crosses the line = 8.00 m/s

s₁ = Distance covered during decelerating = 16.0 m

a₁ = Deceleration

From which we have;

8² = 12² + 2 × a × 16

64 = 144 + 32·a

64 - 144 = 32·a

32·a = -80

a = -80/32 = -2.5 m/s²

From, v₁ = u₁ + a₁·t₁

Where:

t₁ = Time of deceleration

We have;

8 = 12 + (-2.5)·t₁

t₁ = (8 - 12)/(-2.5) = 1.6 seconds

The total time = t + t_t + t₁ =6 + 4 + 1.6 = 11.6 seconds.

6 0
3 years ago
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