22920.0222g of UF6 can be form from 1 metric ton of uranium ore that is 1.55% by mass uranium .
Given ,
Chlorine trifluoride was formerly used in the production of uranium hexafluoride for the U.S. nuclear industry .
The given reaction is :
U(s) +3ClF3 (l) →UF6(l) +3ClF(g)
amount of Uranium ore = 1 metric ton = 10^6 g
volume of ClF3 , V = 12.75L
density of ClF3 , d = 1.88g/ml
mass of uranium , m = 1.55%×10^6g = 1.55×10^4g
molecular mass of uranium , M = 238.02891 g/mol
no of moles of uranium , n = 1.55×10^4g/238.02891g/mol = 65.11 mol
thus 1 mol of uranium produces 1 mol of UF6
then 65.11 mole of uranium produces 65.11 mole of UF6 .
Molecular mass of UF6 = 352.02g/mol
1 mol = 352.02g/mol
65.11 mole of UF6 = 352.02 ×65.11 g = 22920.0222g
Hence , 22920.0222g of UF6 can be form from 1 metric ton of uranium ore that is 1.55% by mass uranium .
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