The percentage error that would be introduced in a 35.0 mL sample of liquid is 2.86%
<h3>Data obatined from the question</h3>
From the question given, the following data were obtained:
- Absolute error = 1 mL
- True measurement = 35 mL
- Perecentage error =?
<h3>How to determine the percentage error</h3>
The percentage error that would be introduced can be obtained as illustrated below:
Percentage error = (Absolute error / True measurement) × 100
Percentage error = (1 / 35) × 100
Percentage error = 2.86%
Thus, percentage error that would be introduced is 2.86%
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