All categories

1 year ago

In order to increase momentum we must increase either the object's

Physics

1 answer:

klasskru [66]1 year ago

7 0

Mass or weight have a good day hope that helps because it helped me

You might be interested in

A roller coaster at the Six Flags Great America amusement park in Gurnee, Illinois, incorporates some clever design technology a

sergeinik [125]

Answer:

a)radius of the arc of the teardrop at the top is 10.58m

b)T = mg

c) the centipetal acceleration at the top is 14.5m/s

Explanation:

Part A

Given that roller coaster is of tear drop shape

So the speed at the top is given as

v = 14.4 m/s

acceleration at the top is given as

a = 2 g

$a = 2(9.8) = 19.6 m/s^2$

now we know the formula of centripetal acceleration as

$a = \frac{v^2}{R}\\$

$19.6 = \frac{14.4^2}{R}\\R = 10.58 m$

Part B

now

the total mass of the car and the ride is M

Let the force exerted by the track be n

By Newton law

$n +Mg =\frac{Mv^2}{r} \\\\n=\frac{Mv^2}{r} -Mg\\\\=M(\frac{v^2}{r}-g )\\\\=M(2g-g)\\\\T=Mg$

Part C

If the radius of the loop is 21.4 m

speed is given by same v = 14.4 m/s

now the acceleration is given as

$a = \frac{v^2}{R}$

$a = \frac{14.4^2}{21.4} \\\\= 9.69 m/s^2$

Now for normal force at the top is given by force equation

$F_n + mg = ma\\F_n = m(a-g)$

The force exerted by the rail is less than zero because acceleration is less than 9.69m/s²

So the normal force would have to point away from the centre, For safe ride this normal force must be positive i.e $a \prec g$

$\frac{v^2}{r} \prec \sqrt{g} \\\\v = \sqrt{rg} \\\\v = \sqrt{21.4 \times 9.8} \\\\v = 14.5m/s$

3 0

3 years ago

How do you calculate the radius of a planets orbit with mass and time ?

Advocard [28]

Answer:

By observing the time between transits, we know the orbital period. Kepler's Third law can be used to determine the orbital radius of the planet if the mass of the orbiting star is known (R3=T2−Mstar/Msun, the radius is in AU and the period is in earth years).

Explanation:

hope this helps!

6 0

3 years ago

Gravity keeps earth orbiting the sun. Earth is about 93,205,679 miles from the sun. What does this distance tell you about the m

Tpy6a [65]

The planets near the sun are smaller (and made out of rock or earth )

6 0

4 years ago

Read 2 more answers

The worker’s pull on the handle of the cart can best be described as a force having

777dan777 [17]

Answer:

both magnitude and direction

Explanation:

The worker's pull on the handle of the cart is best described as the force having both magnitude and direction.

This is a vector quantity
The force is channeled to move the cart in a specific direction.
Also, the pull on the cart can be quantified, and so it have magnitude.
Most physical properties either have magnitude or direction or both.

In this case, the worker is pulling the cart towards a specified direction.

Therefore, the fitting choice is both magnitude and direction.

8 0

4 years ago

If the height of the ramp was 1.2 m above the floor, how long would it take for the marble to hit the ground after it left the r

Evgesh-ka [11]

It would take at less 10 minte i guess this the right awnser

8 0

4 years ago