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Marat540 [252]
4 years ago
14

At a baseball game, you are in the cheap seats and far from the batter. You see the ball moving before you hear the sound of the

bat. Explain this using wave speed. *
Physics
1 answer:
bogdanovich [222]4 years ago
6 0

Answer:

it is he sound of source it uses ur ears to hear something unectpected can u give me brainly plz

Explanation:

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Which contributes most to our average dose of background radiation?
Anuta_ua [19.1K]
C) Natural and Artificial sources
6 0
3 years ago
How much work is done on the electron by the electric field of the sheet as the electron moves from its initial position to a po
miss Akunina [59]

Incomplete question as the charge density is missing so I assume charge density of 3.90×10^−12 C/m².The complete one is here.

An electron is released from rest at a distance of 0 m  from a large insulating sheet of charge that has uniform surface charge density 3.90×10^−12 C/m² .  How much work is done on the electron by the electric field of the sheet as the electron moves from its initial position to a point 3.00×10−2 m from the sheet?

Answer:

Work=1.06×10⁻²¹J

Explanation:

Given Data

Permittivity of free space ε₀=8.85×10⁻¹²c²/N.m²

Charge density σ=3.90×10⁻¹² C/m²

The electron moves a distance d=3.00×10⁻²m

Electron charge e=-1.6×10⁻¹⁹C

To find

Work done

Solution

The electric field due is sheet is given as

E=σ/2ε₀

E=\frac{3.90*10^{-12}C/m^{2}  }{2(8.85*10^{-12}C^{2} /N.m^{2} )}\\ E=0.22V/m

Now we need to find force on electron

F=eE\\F=(1.6*10^{-19}C )(0.22V/m)\\F=3.525*10^{-20}N

Now for Work done on the electron

W=F*d\\W=(3.525*10^{-20} N)(3.00*10^{-2}m)\\W=1.06*10^{-21}J

4 0
4 years ago
A loaded 500 kg sled is traveling on smooth horizontal snow at 5 m/s when it suddenly comes to a rough region. The region is 10
sergejj [24]

Answer:

400 N

Explanation:

Change of Kinetic Energy to Friction Wok

∆KE = W

½ x m x (v(5)² - v(3)²) = f x d

½ x 500 x (5² - 3²) = f x 10

250 x (25 - 9) = f x 10

25 x 16 = f

f = 400 N

6 0
3 years ago
The force of gravity on an object is known as its mass. Please select the best answer from the choices provided T F
hram777 [196]

the answer is false

3 0
3 years ago
The magnitude E of an electric field depends on the radial distance r according to E = A/r4, where A is a constant with unit vol
Lesechka [4]

Answer:

\Delta V = 0.053 A

Explanation:

Electric field in a given region is given by equation

E = \frac{A}{r^4}

as we know the relation between electric field and potential difference is given as

\Delta V = -\int E. dr

so here we have

\Delta V = - \int (\frac{A}{r^4}) .dr

\Delta V = \frac{A}{3r_1^3} - \frac{A}{3r_2^3}

here we know that

r_1 = 1.71 m  and r_2 = 2.89 m

so we will have

\Delta V = \frac{A}{3}(\frac{1}{1.71^3} - \frac{1}{2.89^3})

so we will have

\Delta V = 0.053 A

8 0
3 years ago
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