F = m*a
5000 = 2000 * x
5000/2000 = x
2.5 = x
2.5m/s^2 = a
the object distance of both lenses are positive.
Explanation:
An perfect mass less spring, attached at one end and with a free mass attached at the other end, will have a distinct frequency of oscillation depending on its constant spring and mass. On the other hand, a spring with mass along its length will not have a characteristic frequency of oscillation.
Alternatively, based on its spring constant and mass per length, it will now have a wave Speed. It would be possible to use all wavelengths and frequencies, as long as the component fλ= S, where S is the spring wave size. If that sounds like longitudinal waves, like solid sound waves.
Answer:
θ = 20.9 rad
Explanation:
In a blender after a short period of acceleration the blade is kept at a constant angular velocity, for which we can use the relationship
w = θ / t
θ = w t
if we know the value of the angular velocity we can find the angular position, we must remember that all the angles must be in radians
suppose that the angular velocity is w = 10 rpm, let us reduce to the SI system
w = 10 rpm ![(\frac{2\pi rad}{1 rev}) ( \frac{1 min}{60 s} )](https://tex.z-dn.net/?f=%28%5Cfrac%7B2%5Cpi%20%20rad%7D%7B1%20rev%7D%29%20%28%20%5Cfrac%7B1%20min%7D%7B60%20s%7D%20%29)
= 1,047 rads
let's calculate
θ = 1,047 20
θ = 20.9 rad