a) U = 0 J
k = 0.383 J
E = 0.383 J
b) U = 0.0228 J
k = 0.155 J
E = 0.383 J
c) U = 0.1104 J
k = 0.272 J
E = 0.383 J
d) U = 0.248 J
k = 0.177 J
E = 0.383 J
<h3>Method for solving:</h3>The equations for kinetic energy is:
k= 1/2*m*
The equation for elastic potential energy is:
U= 1/2*ks*
Where,
m= mass of the block
v= velocity
ks= spring constant
x= displacement of the spring
(a)when compression= 0 cm
U= 1/2*ks*
U= 1/2*552*
= 0 J
Kinetic energy:
k= 1/2*m*
k= 1/2*(1.05)*
k= 0.383 J
Mechanical energy:
E= k + U
E= 0.383+0
E= 0.383 J
(b) spring potential = ?
U= 1/2* 457 N/m*
U= 0.0228 J
Since the mechanical energy must remain constant, we may calculate the kinetic energy using the mechanical energy equation:
E= k + U
0.383= k + 0.0228
k= 0.383 - 0.228
k= 0.155
(c)spring constant when x= 0.02
U= 1/2*552*
U= 0.1104 J
Using the equation of mechanical energy:
E= k +U
0.383= k+ 0.1104
k= 0.383 - 0.1104
k= 0.272 J
(d) U= 1/2*552*
U= 0.2484 J
E= 0.383 J
k = E - U
k= 0.383- 0.206
k= 0.177
To learn more about spring potential energy visit:
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Answer:
v_{ average} = 5.57
Explanation:
The most probable value of a measure is
v_average = ∑ x_i
where N is the number of measurements
in tes case N = 3
v_{average} = ⅓ (5.63 +5.54 + 5.53)
V_{average} = 5,567
The number of significant figures must be equal to the number of figures that have the least in the readings.
v_{ average} = 5.57