Answer:
Force of kinetic friction, Fk = 6N
Explanation:
Given the following data;
Coefficient of kinetic friction, μ = 0.2
Normal force, Fn=30N
To find the Force of kinetic friction;
Mathematically, the force of kinetic friction is given by the formula;
Fk = μFn
Where;
- Fk represents the force of kinetic friction.
- μ represents the coefficient of friction.
- Fn represents the normal force.
Substituting into the equation, we have;
Fk = 0.2*30
Fk = 6N
Therefore, the force of kinetic friction is 6N.
1. Stop transmitting start and stop sending photons. This is typical morse code like transmissions of information. By varying the pattern of starts stops you vary the information sent. Also used in digital communications over radios, modems, and pulse dialing over radio/phones.
<span>2. Change the frequency. You use a pattern of shorter and longer wavelengths of radio waves higher and lower energies of individual photons to transmit information. This is frequency modulation </span>
Speed is a scalar quantity, meaning it has no direction. Velocity is a vector, meaning that it has a specific direction associated with it.
Many people use these interchangeably, but it is not always correct to do so.
Answer: vf = 51 m/s
d = 112 m
Explanation: Solution attached:
To find vf we use acceleration equation:
a = vf - vi / t
Derive to find vf
vf = at + vi
Substitute the values
vf = 3.5 m/s² ( 8.0 s) + 23 m/s
= 51 m/s
To solve for distance we use
d = (∆v)² / 2a
= (51 m/s - 23 m/s )² / 2 ( 3.5 m/s²)
= (28 m/s)² / 7 m/s²
= 784 m/s / 7 m/s²
= 112 m