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victus00 [196]
3 years ago
9

What occurs when kcl(s is added to water?

Chemistry
1 answer:
Mama L [17]3 years ago
8 0
When KCL, which is an ionic compound is added to water it will dissociate and or ionize completely forming the ions of K+ and Cl-. The resulting solution would be a neutral solution, as the K+ is a cation of a strong base and Cl- is an anion of a strong acid, and whenever a strong base reacts with a strong acid, a neutral salt is produced
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Which of the following atoms would gain two electrons to fill its valence energy level?
Harlamova29_29 [7]

The atom that would gain two electrons to fill its valence energy level is S(sulfur)

This is because s (sulfur) is in atomic number 16 with 2.8.6 of [Ne] 3s^2 2p^4 electronic configuration. This implies that sulfur has 6 valence electron and therefore it require two electron to fill its valence energy level and obtain 18 rule electrons.

5 0
3 years ago
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Determine how many moles of CO2 are required to produce 11.0 mol of glucose,
drek231 [11]

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Determine how many moles of CO2 are required to produce 11.0 mol of glucose,

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7 0
2 years ago
The morning temperature in a city is 41°F. If a sunny, mild day is forecast, which temperature is most likely for 2:00 p.m.?
romanna [79]

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2 years ago
How many molecules are in 100 g of C6H120,?*​
Grace [21]

Answer:

3.37 × 10²³ molecules

Explanation:

Given data:

Mass of C₆H₁₂O₆ = 100 g

Number of molecules = ?

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Number of moles = mass/molar mass

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6 0
3 years ago
The mole fraction of iodine, i2, dissolved in dichloromethane, ch2cl2, is 0.115. what is the molal concentration, m, of iodine i
german
The molality of a solute is equal to the moles of solute per kg of solvent. We are given the mole fraction of I₂ in CH₂Cl₂ is <em>X</em> = 0.115. If we can an arbitrary sample of 1 mole of solution, we will have:

0.115 mol I₂

1 - 0.115 = 0.885 mol CH₂Cl₂

We need moles of solute, which we have, and must convert our moles of solvent to kg:

0.885 mol x 84.93 g/mol = 75.2 g CH₂Cl₂ x 1 kg/1000g = 0.0752 kg CH₂Cl₂

We can now calculate the molality:

m = 0.115 mol I₂/0.0752 kg CH₂Cl₂
m = 1.53 mol I₂/kg CH₂Cl₂

The molality of the iodine solution is 1.53.
5 0
3 years ago
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