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Ray Of Light [21]
1 year ago
11

The discharge of phosphate in detergents to the environment has led to imbalances in the life cycle of freshwater lakes. A chemi

st uses a spectrometric method to measure total phosphate and obtains the following data for known standards: (a) Draw a curve of absorbance vs. phosphate concentration.
Chemistry
1 answer:
alina1380 [7]1 year ago
3 0
<h3>What is spectrometric method?</h3>
  • A technique called spectrophotometry uses light intensity measurements as a beam of light travels through a sample solution to determine how much a chemical compound absorbs light.
  • Every chemical either absorbs or transmits light across a specific spectrum of wavelengths, according to the fundamental principle.
  • There are two main techniques used among the various forms of spectrophotometry:
  • ultraviolet-visible range spectrophotometry, which examines the reflectance of certain spectra,
  • and absorption spectrophotometry, which examines the absorption of radiation and particular spectra of light.
  • Applications of spectrophotometry are useful for determining how well gases, liquids, and solids transmit, reflect, and absorb light.

Learn more about spectrometric method here:

brainly.com/question/18339003

#SPJ4

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I would think that the answer would be three

Because of the prefix tri- in "tigonal"

Tri- means 3, as in tricycle or triangle

So, it would make sense for the answer to be 3
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An atom has a diameter of 2.50 Å and the nucleus of that atom has a diameter of 9.00×10−5 Å . Determine the fraction of the volu
chubhunter [2.5K]

Answer:

The fraction of the volume of the atom that is taken up by the nucleus is 4.6656\times 10^{-14}.

The density of a proton is 6.278\times 10^{14} g/cm^3.

Explanation:

Diameter of the atom ,d = 2.50 Å

Radius of the atom ,r = 0.5 d=0.5 × 2.50 Å = 1.25Å

Volume of the sphere= \frac{4}{3}\pi r^3

Volume of atom = V

V=\frac{4}{3}\pi r^3..[1]

Diameter of the nucleus ,d' = 9.00\times 10^{-5}\AA

Radius of the nucleus ,r' = 0.5 d'=0.5\times 9.00\times 10^{-5}\AA=4.5\times 10^{-5}\AA

Volume of nucleus = V'

V=\frac{4}{3}\pi r'^3..[2]

Dividing [2] by [1]

\frac{V'}{V}=\frac{\frac{4}{3}\pi r'^3}{\frac{4}{3}\pi r^3}

=\frac{r'^3}{r^3}=\frac{(4.5\times 10^{-5}\AA)^3}{(1.25 \AA)^3}

\frac{V'}{V}=4.6656\times 10^{-14}

The fraction of the volume of the atom that is taken up by the nucleus is 4.6656\times 10^{-14}.

Diameter of the proton ,d = 1.72\times 10^{-15} m = 1.72\times 10^{-13} cm

1 m = 100 cm

Radius of the proton,r = 0.5 d=0.5\times 1.72\times 10^{-13} cm=8.6\times 10^{-14} cm

Volume of the sphere= \frac{4}{3}\pi r^3

Volume of atom = V

V=\frac{4}{3}\times 3.14\times (8.6\times 10^{-14} cm)^3=2.664\times 10^{-39}cm^3

Mass of proton, m = 1.0073 amu = 1.0073\times 1.66054\times 10^{-24} g

1 amu = 1.66054\times 10^{-24} g

Density of the proton : d

d=\frac{m}{V}=\frac{1.0073\times 1.66054\times 10^{-24} g}{2.664\times 10^{-39}cm^3}=6.278\times 10^{14} g/cm^3

The density of a proton is 6.278\times 10^{14} g/cm^3.

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