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IrinaVladis [17]
2 years ago
8

In a certain region of space, a uniform electric field is in the x direction. A particle with negative charge is carried from x=

20.0 cm to x=60.0cm. (ii) Has the particle moved to a position where the electric potential is (a) higher than before, (b) unchanged, (c) lower than before, or (d) unpredictable?
Physics
1 answer:
MakcuM [25]2 years ago
3 0

In a certain region of space, a uniform electric field is in the x direction. A particle with negative charge is carried from x=20.0 cm to x=60.0cm.

The particle moved to a position where the electric potential is

(a) higher than before

(b) unchanged

(c) lower than before

(d) unpredictable

The correct option is Option c)

Where is the electric potential, when the particle moved?

The particle moved to a position where the electric potential is lower than before because the potential decreases in the direction of the electric field.

Electric potential energy is the energy that is required when we have to move a charge against the applied electric field. We need more energy to move a charge further in the electric field, but also more energy to move it through a stronger electric field.

To learn more about electric potential, refer to:

brainly.com/question/21808222

#SPJ4

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Let us assume that pulley is mass less.

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Hence\ the\ frictional\ force\ F=\mu N

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                           m_{1} g-T=m_{1}a             [1]

                           T-\mu m_{2}g= m_{2} a   [2]

                           ---------------------------------------------------

                           [m_{1} -\mu m_{2} ]g=[m_{1} +m_{2} ]a

                           a=\frac{m_{1}-\mu m_{2}} {m_{1}+ m_{2}}*g

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                           a=\frac{0.74}{3} *9.8\ m/s^2

                           a=2.417 m/s         [ans]

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