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3 years ago

In one experiment 7.62 g of Fe are allowed to react with 8.67 g of S

Chemistry

1 answer:

vichka [17]3 years ago

4 0

calculate moles of both reagents given and the moles of FeS that each of them would form if they were in excess

moles = mass / molar mass

moles Fe = 7.62 g / 55.85 g/mol

= 0.1364 moles

1 mole Fe produces 1 mole FeS

Therefore 7.62 g Fe can form 0.1364 moles FeS

moles S = 8.67 g / 32.07 g/mol

= 0.2703 moles S

1 mole S can from 1 moles FeS

So 8.67 g S can produce 0.2703 moles FeS

The limiting reagent is the one that produces the least product. So Fe is limiting.

The maximum amount of FeS possible is from complete reaction of all the limiting reagent.

We have already determined that the Fe can form up to 0.1364 moles of FeS, so this is max amount of FeS you can get.

Convert to mass

hope this helps :)

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