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Viktor [21]
1 year ago
10

What distance in kilometers can you drive if your car gets 14.00 kilometers per liter and you have 35.00 liters of gas?​

Chemistry
1 answer:
agasfer [191]1 year ago
7 0

2.5 km is the distance you can travel if a car gets 14 kilometers per liter and have 35 liters of gas.

Total distance traveled in 1 liter = 14 km

Total gas in the car = 35 liters

We have to find how much distance can be covered in in35 liters of gas.

Distance is the length of the path traveled between two points. It is the total movement of an object in a direction. It measures length.

Distance = 35/14

Or, distance = 2.5 km

Therefore, the total distance that can be covered by a car in 35 liters of gas is 2.5 km.

To learn more about distance, visit: brainly.com/question/15172156

#SPJ9

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3 years ago
Alkenes ______
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Answer:

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6 0
3 years ago
You have a 2.0 mL sample of acetic acid (molar mass 60.05 g/mol) of unknown concentration. You titrate it to its endpoint with 2
Katyanochek1 [597]

<u>Answer:</u> The mass of acetic acid used is 0.12 grams

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is CH_3COOH

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?M\\V_1=2.0mL\\n_2=1\\M_2=0.1M\\V_2=20.0mL

Putting values in above equation, we get:

1\times M_1\times 2.0=1\times 0.1\times 20.0\\\\M_1=\frac{1\times 0.1\times 20.0}{1\times 2.0}=1M

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of acetic acid = ? g

Molar mass of acetic acid = 60.05 g/mol

Molarity of solution = 1 M

Volume of the solution = 2.0 mL

Putting values in above equation, we get:

1mol/L=\frac{\text{Mass of acetic acid}\times 1000}{60.05g/mol\times 2.0}\\\\\text{Mass of acetic acid}=\frac{1\times 60.05\times 2}{1000}=0.12g

Hence, the mass of acetic acid used is 0.12 grams

5 0
3 years ago
NaOH + HCl → NaCl + H2O. What mass of water forms when 2.75 × 10–4 mol NaOH reacts completely? given the equation, 2.75 × 10–4 m
Hoochie [10]
The balanced chemical reaction is written as:

<span>NaOH + HCl → NaCl + H2O

We are given the amount of sodium hydroxide to be used up in the reaction. This will be the starting point for the calculation. 

2.75 x 10^-4 mol NaOH ( 1 mol H2O / 1 mol NaOH ) ( 18.02 g H2O / 1 mol H2O ) = 4.96 x 10^-3 g H2O</span>
5 0
3 years ago
Read 2 more answers
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