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Viktor [21]
1 year ago
10

What distance in kilometers can you drive if your car gets 14.00 kilometers per liter and you have 35.00 liters of gas?​

Chemistry
1 answer:
agasfer [191]1 year ago
7 0

2.5 km is the distance you can travel if a car gets 14 kilometers per liter and have 35 liters of gas.

Total distance traveled in 1 liter = 14 km

Total gas in the car = 35 liters

We have to find how much distance can be covered in in35 liters of gas.

Distance is the length of the path traveled between two points. It is the total movement of an object in a direction. It measures length.

Distance = 35/14

Or, distance = 2.5 km

Therefore, the total distance that can be covered by a car in 35 liters of gas is 2.5 km.

To learn more about distance, visit: brainly.com/question/15172156

#SPJ9

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9. Given the following reaction:CO (g) + 2 H2(g) CH3OH (g)In an experiment, 0.45 mol of CO and 0.57 mol of H2 were placed in a 1
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Answer:

Keq=11.5

Explanation:

Hello,

In this case, for the given reaction at equilibrium:

CO (g) + 2 H_2(g) \rightleftharpoons CH_3OH (g)

We can write the law of mass action as:

Keq=\frac{[CH_3OH]}{[CO][H_2]^2}

That in terms of the change x due to the reaction extent we can write:

Keq=\frac{x}{([CO]_0-x)([H_2]_0-2x)^2}

Nevertheless, for the carbon monoxide, we can directly compute x as shown below:

[CO]_0=\frac{0.45mol}{1.00L}=0.45M\\

[H_2]_0=\frac{0.57mol}{1.00L}=0.57M\\

[CO]_{eq}=\frac{0.28mol}{1.00L}=0.28M\\

x=[CO]_0-[CO]_{eq}=0.45M-0.28M=0.17M

Finally, we can compute the equilibrium constant:

Keq=\frac{0.17M}{(0.45M-0.17M)(0.57M-2*0.17M)^2}\\\\Keq=11.5

Best regards.

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