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podryga [215]
3 years ago
9

What is the specific heat of titanium in j/(g⋅∘c) if it takes 89.7 j to raise the temperature of a 33.0 g block by 5.20 ∘c?

Chemistry
2 answers:
antoniya [11.8K]3 years ago
6 0

Answer:

0.52  \frac{J}{g~^{\circ}C}

Explanation:

The to start with the equation:

Q=m~CpΔT

Where:

Q= Heat (J)

m= mass (in grams)

Cp= Specific heat (\frac{J}{g~^{\circ}C})

ΔT=Tfinal-Tinitial

Then we have to put the values into the equation:

89.7~J=33.0~g*Cp*5.20^{\circ}C

The next step would be the to solve for "<u>Cp</u>":

Cp=\frac{89.7~J}{30.0~g*5.20^{\circ}C}=0.52  \frac{J}{g~^{\circ}C}

larisa [96]3 years ago
5 0
Specific  heat  capacity  is  the  amount  of  energy  required  to  raise one  gram  of  substances by 1 degree  celsius .  Therefore  specific  heat  capacity  for  tatanium  is  89.7j /(  33.0g  x5.2 degree celsius) = 0.52j/g  degree celcius
Molar mass for tatanium   is  47.9 g/mole
heat  is  therefore 47.9  g/mole  x 0.52j/g  =24.9j/mole
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Gala2k [10]

Explanation:

The equation of the reaction is given as;

Be + 2HCl → BeCl2 + H2

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1 mol of Be produces 1 mol of BeCl2

Converting to mass;

Mass = Molar mass  *  Number of moles

9.01g of Be produces 79.92g of BeCl2

xg of Be produces 25g of BeCl2

Solving for x;

x = 25 * 9.01 / 79.92

x = 2.82 g

What is the mass of hydrochloric acid required to produce 25.0g of beryllium chloride? g

Converting 25.0g of beryllium chloride to moles;

Number of moles = Mass / Molar mass

Number of moles = 25 / 79.92 = 0.3128 mol

2 mol of HCl produces 1 mol of BeCl2

x mol of HCl would produce 0.3128 mol of BeCl2

solving for x;

x = 0.3128 * 2 = 0.6256 mol

Converting to mass;

Mass = 0.6256 * 36.5 = 22.83 g

What is the mass of hydrogen gas produced when 25.0g of beryllium chloride is also produced? g

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From the equation;

1 mol of H2 is produced alongside 1 mol of BeCl2

This means;

0.3128 mol of H2 would also be produced alongside 0.3128 mol of BeCl2

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3 0
3 years ago
What is needed to burn the candle (reactant)?
Alexus [3.1K]

Answer:

wax, candlewick, and oxygen

Explanation:

The burning of the candle is both a physical as well as a chemical change. The reactants are the substances or the raw materials that are required for a reaction to the process. In the process of burning a candle, the reactants are the fuel which includes wax and wick, and oxygen which is found in the air. The products found at the end of the reaction are carbon dioxide and water vapor.

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jek_recluse [69]

Answer : The correct option is (d) a solution of 0.10 M NaOH

Explanation :

<u>(a) a solution of pH 3.0</u>

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Now we have to calculate the OH^- concentration.

pOH=-\log [OH^-]

11=-\log [OH^-]

[OH^-]=1.0\times 10^{-11}M

Thus, the OH^- concentration is, 1.0\times 10^{-11}M

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As we know that 1 mole of HNO_2 in a solution dissociates to give 1 mole of H^+ ion and 1 mole of NO_2^- ion.

So, 1\times 10^{-4}M of HNO_2 in a solution dissociates to give 1\times 10^{-4}M of H^+ ion and 1\times 10^{-4}M of NO_2^- ion.

The concentration of H^+ ion is 1\times 10^{-4}M

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