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aniked [119]
2 years ago
15

The fuel for a jet engine has a density of 1.32 slug/ft3. if the total volume of fuel tank a is 50 ft3, determine the weight of

the fuel when the tanks are completely full?
Physics
1 answer:
inessss [21]2 years ago
6 0

The weight of the fuel when the tank is filled is 2.13 kip.

The density of the fuel of the jet engine= 1.32 slug/ft³

The total volume of the fuel that can be filled in the fuel tank of a jet engine = 50 ft³

The specific weight of the fuel when the tank is filled is,

\gamma  =  p \times g

\gamma  = 1.32 \times   32.2

\gamma  = 42.504 \: ib/ft ^{3}

The specific weight of the fuel when the tank is filled is 42.504 ib/ft ³.

The weight of the fuel when the tank is filled is,

w =  \gamma  \times ∀

w  = 42.5.4 \times 50

w = 2.13 \: kip

The weight of the fuel is 2.13 kip.

Therefore, the weight of the fuel when the tank is filled is 2.13 kip.

To know more about specific weight, refer to the below link:

brainly.com/question/13178675

#SPJ4

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Answer:

The value is \eta  =  54.4 \%

Explanation:

From the question we are told that

    The work input is  W = ( 245 + A ) \  J

     The heat delivered is Q =  (142 + B) \  J

      The value of A is  A =  14

        The value of B  is  B  = 72

Generally the efficiency of the heat engine is mathematically represented as

          \eta  =  \frac{W}{Q_t}

Here  Q_t is the total out energy produce by the heat engine and this is mathematically represented as

           Q_t= Q + W

=>         Q_t=  245 + A + 142 + B

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               \eta  =  \frac{245 + A }{390 + A+ B}

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=>          \eta  =  0.544 *100

=>          \eta  =  54.4 \%

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