I think the answer is A) Cindy biked westward at 30km/h. I'm sorry if I'm wrong. If that's not correct then it's definitely C) A dog runs an average of 8mp/h. I hope this helps. :)
E=ERBIUM
L=LITHIUM
E=EINSTEINIUM
M=MAGNESIUM
E=EUROPIUM
N=NITROGEN
T=TITANIUM
S=SULPHURDIOXIDE
Answer:
The velocity of the players will be <u>2.88 m/s</u> in the <u>east</u> direction.
Explanation:
Let 'v' be the velocity of the players after collision.
Consider the east direction as positive direction.
Given:
Mass of the first player is,
kg
Initial velocity of the first player is,
m/s
Mass of the second player is,
kg
Initial velocity of the second player is,
m/s
In order to solve this problem we use the law of conservation of momentum which says that the total momentum must be conserved before and after the collision. So we can write:

Solving for v, we get:

Therefore, their velocity after the collision is 2.88 m/s.
The sign of the velocity after collision is positive. So, the players will move in the east direction only after collision.
To look for the acceleration, it will come from:
vf^2=v0^2+2ad
where:
vf = final velocity = 0
v0 = initial velocity =251 m/s
a = acceleration
d= distance traveled = 0.237 m
0=251^2+2a(0.237 )
a= -251 ^2 / (2*0.237) =-132 913.502 m/s/s
we find the force from:
F = ma = 0.0115kg*(-1.32x10^5m/s/s) = -1518 N
the negative sign shows that the force is in the direction contradictory the
bullet's motion
The best conclusion that can be drawn is that D) A current does not flow in the wire