Answer:
q = -6464.9 kJ
Explanation:
We are given that the heat of combustion is ∆H° = −394 kJ per mol of carbon.Therefore what we need to do is calculate how many moles of C are in the lump of coal by finding its mass since the density is given.
vol = 5.6 cm x 5.1 cm x 4.6 cm = 131.38 cm³
m = d x v = 1.5 g/cm³ x 131.38 cm³ = 197.06 g
mol C = m/MW = 197.06 g/ 12.01g/mol = 16.41 mol
q = −394 kJ /mol C x 16.41 mol C = -6464.9 kJ
Answer:


Explanation:
<u>First mixture</u>:
40 wt% methanol - 60 wt% water 200 kg


<u>Second mixture</u>:
70 wt% methanol - 30 wt% water 150 kg


Final mixture:




If, the compositions are constant, the only variables are the mass of each mixture used in the final one, so there can be only one independent balance.
Sugar cube is my answer
Hope this helps!
Let me know if i'm wrong.
Answer:
B. Composed of molecules relatively far apart.
Explanation:
The gas we call "air" has molecules that are relatively far apart.