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Oksi-84 [34.3K]
3 years ago
15

A sulfuric acid solution containing 571.6 g of H2SO4 per liter of aqueous solution has a density of 1.329 g/cm^3.Calculate:a. Ma

ss percentageb. Mole fractionc. Molalityd. molarity of H2SO4 in this solution.
Chemistry
1 answer:
12345 [234]3 years ago
8 0

Given :

Mass of H_2SO_4 is 571.6 g per liter .

Density of solution , \rho=1.329\ g/cm^3 .

To Find :

a. Mass percentage

b. Mole fraction

c. Molality

d. molarity of H2SO4 in this solution.

Solution :

Molar mass of H_2SO_4 , m = 1329 g/mol .

a ) Mass of H_2SO_4 contain in 1 liter is 1329 g .

mass \ \%=\dfrac{571.6}{1329}\times 100=43.01 \%

b ) Moles of H_2SO_4 = \dfrac{571.6\ g}{98\g/mol}=5.83\ mol .

Moles of H_2O = \dfrac{1329-571.6\ g}{18\ g/mol}=42.08\ mol .

Mole fraction =\dfrac{5.83}{5.83+42.08}=0.12 .

c ) Molarity of H_2SO_4  =\dfrac{5.83\ mol}{1 \ L}=5.83\ M .

Hence , this is the required solution .

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