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Natalka [10]
3 years ago
7

A Porsche sports car can accelerate at 8.8 m/s^2. Determine its acceleration in km/h^2.

Physics
1 answer:
finlep [7]3 years ago
6 0

Answer:

The acceleration expressed in the new units is 114.048 Km/h^{2}

Explanation:

To convert from m/s^{2} to Km/h^{2} it is necessary to remember that there are 1000 meters in 1 kilometer and 3600 seconds in 1 hour:

Then by means of a rule of three it is get:

8.8\frac{m}{s^{2}}.(\frac{1Km}{1000m}).(\frac{3600s}{1h})^{2}

8.8\frac{m}{s^{2}}.(\frac{1Km}{1000m}).(\frac{12960000s^{2}}{1h^{2}})

Hence, the units of meters and seconds will cancel. Notice the importance of square the ratio 3600s/1h, so that way they can match with the other units:

114.048 Km/h^2

So the acceleration expressed in the new units is 114.048 Km/h^2.

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What is the peak emf generated by rotating a 940-turn, 24 cm diameter coil in the Earth’s 5·10−5 T magnetic field, given th
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The peak emf generated by the coil is 2.67 V

Explanation:

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diameter, d = 24 cm = 0.24 m

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time, t = 5 ms = 5 x 10⁻³ s

peak emf, V₀ = ?

V₀ = NABω

Where;

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A is the area

B is the magnetic field strength

ω is the angular velocity

V₀ = NABω and ω = 2πf = 2π/t

V₀ = NAB2π/t

A = πd²/4

V₀ = N x (πd²/4) x B x (2π/t)

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