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Natalka [10]
3 years ago
7

A Porsche sports car can accelerate at 8.8 m/s^2. Determine its acceleration in km/h^2.

Physics
1 answer:
finlep [7]3 years ago
6 0

Answer:

The acceleration expressed in the new units is 114.048 Km/h^{2}

Explanation:

To convert from m/s^{2} to Km/h^{2} it is necessary to remember that there are 1000 meters in 1 kilometer and 3600 seconds in 1 hour:

Then by means of a rule of three it is get:

8.8\frac{m}{s^{2}}.(\frac{1Km}{1000m}).(\frac{3600s}{1h})^{2}

8.8\frac{m}{s^{2}}.(\frac{1Km}{1000m}).(\frac{12960000s^{2}}{1h^{2}})

Hence, the units of meters and seconds will cancel. Notice the importance of square the ratio 3600s/1h, so that way they can match with the other units:

114.048 Km/h^2

So the acceleration expressed in the new units is 114.048 Km/h^2.

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If jack was traveling at 100 miles in 2 hours what was his velocity in miles per second​
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1 hour is 3600 seconds. In 2 hours, it would be 7200 seconds.  Divide the amount of miles by seconds. 100/7200=.01388..

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2 years ago
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irga5000 [103]

Answer:

Explanation:

solution is found below

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3 years ago
What is the volume of an irregularly shaped object that has a mass 3.0 grams and a density of 6.0 g/mL
pogonyaev

Answer: The volume of an irregularly shaped object is 0.50 ml

Explanation:

To calculate the volume, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of object = 6.0g/ml

mass of object = 3.0 g

Volume of object = ?

Putting in the values we get:

6.0g/ml=\frac{3.0g}{\text{Volume of substance}}

{\text{Volume of substance}}=0.50ml

Thus the volume of an irregularly shaped object is 0.50 ml

4 0
3 years ago
A student is building a simple circuit with a battery, light bulb, and copper wires. When she connects the wires to the battery
denis23 [38]
It’s will be B because the circuit had a open or close so if that doesn’t work than it’s because it’s open
5 0
3 years ago
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An 84.0 kg sprinter starts a race with an acceleration of 1.76 m/s2. If the sprinter accelerates at that rate for 11 m, and then
gulaghasi [49]

Answer:

t=17.838s

Explanation:

The displacement is divided in two sections, the first is a section with constant acceleration, and the second one with constant velocity. Let's consider the first:

The acceleration is, by definition:

a=\frac{dv}{dt}=1.76

So, the velocity can be obtained by integrating this expression:

v=1.76t

The velocity is, by definition: v=\frac{dx}{dt}, so

dx=1.76tdt\\x=1.76\frac{t^{2}}{2}.

Do x=11 in order to find the time spent.

11=1.76\frac{t^2}{2}\\ t^2=\frac{2*11}{76} \\t=\sqrt{12.5}=3.5355s

At this time the velocity is: v=1.76t=1.76*3.5355s=6.2225\frac{m}{s}

This velocity remains constant in the section 2, so for that section the movement equation is:

x=v*t\\t=\frac{x}{v}

The left distance is 89 meters, and the velocity is 6.2225\frac{m}{s}, so:

t=\frac{89}{6.2225}=14.303s

So, the total time is 14.303+3.5355s=17.838s

7 0
2 years ago
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