Answer:
1.52 x x (cm3 STP) / -s
Explanation:
This is a permeability problem ithat asked to compute the diffusion flux of water vapor through a 2-mm thick sheet of polypropylene. The permeability coefficient of H2O through PP is
38 x (STP)-cm / -s-Pa.
Thus, from Equation
J= x ΔP/Δx = x / Δx
here
P1= 2 kPa =2,000 Pa
P2= 11 kPa = 11,000 Pa
J = (38 X x (cm3 STP)(cm) / -s-Pa) (10,000 Pa - 2,000 Pa / 0.2 cm)
= 1.52 x x (cm3 STP) / -s
Answer:
A: density and gravity
Explanation:
The Froude Number is defined as a dimensionless parameter that measures the ratio of the force of inertia on an element of fluid to the weight of the fluid element. In simple terms, it's the force of inertia divided by the gravitational force.
Froudes number is usually expressed as;
Fr = v/√(gd)
Where;
Fr = froude number
v = velocity
g = gravitational acceleration = specific weight/density
d = depth of flow
Now, to calculate the corresponding speed and force in the prototype, it means we have to use equal froude number and thus this will mean that it has to be dominated by gravity and density.
Answer:
yes it is
Explanation:
it's an extremely good phone in my opinion
Answer:
The external pressure is p = -21.9 psf or p = -8.85 psf
Explanation:
Given :
Velocity of wind, v = 120 mi / hr
(wind direction factor)
= topographical factor (for flat terrain)
= velocity pressure at height h
But for height h = 30 ft, = 0.98 (from table)
= 36.16
Now, , so (from table)
where, p = external pressure
G = 0.85 = gust factor (for typical rigid building)
(internal pressure co efficient)
Therefore putting the values,
p = -21.9 psf or p = -8.85 psf
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