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Arada [10]
2 years ago
14

What will be the new volume of a 250 mL sample of gas at 300 K and 1 atm if heated to 350 K at 1 atm? Law used:

Chemistry
2 answers:
ladessa [460]2 years ago
3 0
Using Charles's law; which states that the volume of an ideal gas is directly proportional to the absolute temperature at constant pressure. 
That is; V α T
Hence; V1/T1 = V2/T2 = constant
V2 =  V1 × (T2/T1)
    = 250 × (350/300) = 291.67 mL
Therefore; the new volume will be 291.67 mL
maw [93]2 years ago
3 0

<u>Answer:</u> The final volume of the system is 291.66 mL.

<u>Explanation:</u>

To calculate the final volume of the system, we use the equation given by Charles' Law.

This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=250mL\\T_1=300K\\V_2=?mL\\T_2=350K

Putting values in above equation, we get:

\frac{250}{300K}=\frac{V_2}{350K}\\\\V_2=291.66mL

Hence, the final volume of the system is 291.66 mL.

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A 1.00 g sample of octane (C8H18) is burned in a bomb calorimeter with a heat capacity of 837J∘C that holds 1200. g of water at
lubasha [3.4K]

Answer:

The heat of combustion for 1.00 mol of octane is  -5485.7 kJ/mol

Explanation:

<u>Step 1:</u> Data given

Mass of octane = 1.00 grams

Heat capacity of calorimeter = 837 J/°C

Mass of water = 1200 grams

Temperature of water = 25.0°C

Final temperature : 33.2 °C

<u> Step 2:</u> Calculate heat absorbed by the calorimeter

q = c*ΔT

⇒ with c = the heat capacity of the calorimeter = 837 J/°C

⇒ with ΔT = The change of temperature = T2 - T1 = 33.2 - 25.0 : 8.2 °C

q = 837 * 8.2 = 6863.4 J

<u>Step 3:</u> Calculate heat absorbed by the water

q = m*c*ΔT

⇒ m = the mass of the water = 1200 grams

⇒ c = the specific heat of water = 4.184 J/g°C

⇒ ΔT = The change in temperature = T2 - T1 = 33.2 - 25  = 8.2 °C

q = 1200 * 4.184 * 8.2 =  41170.56 J

<u>Step 4</u>: Calculate the total heat

qcalorimeter + qwater = 6863.4 + 41170. 56 = 48033.96 J  = 48 kJ

Since this is an exothermic reaction, there is heat released. q is positive but ΔH is negative.

<u>Step 5</u>: Calculate moles of octane

Moles octane = 1.00 gram / 114.23 g/mol

Moles octane = 0.00875 moles

<u>Step 6:</u> Calculate heat combustion for 1.00 mol of octane

ΔH = -48 kJ / 0.00875 moles

ΔH = -5485.7 kJ/mol

The heat of combustion for 1.00 mol of octane is  -5485.7 kJ/mol

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2 years ago
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2\text{Mn} + 6\text{HI} \longrightarrow 3 \text{H}_2+2\text{MnI}_3

3 0
2 years ago
The energy of a photon is ________ proportional to its wavelength. The energy of a photon is ________ proportional to its freque
topjm [15]

Answer: Inversely  ,   Directly

Explanation:

The energy of a photon is inversely proportional to its wavelength and directly proportional to its frequency.

As can be seen from this equation;

E = hv  = h c / ∧

Where E = Energy of a photon

           v = Frequency

           h = Planck Constant

           c = speed of light

           ∧  = Wave length

4 0
3 years ago
Write the balanced equation for a reaction between aqueous nitric acid (HNO3) and solid lithium metal (this is a single replacem
Lemur [1.5K]

<u>Answer:</u> The equation is given below.

<u>Explanation:</u>

Single replacement reactions are the chemical reactions in which more reactive metal displaces a less reactive metal from its chemical reaction. General equation for these reactions is given by the equation:

A+BC\rightarrow AC+B

Metal A is more reactive than metal B.

The reactivity of metals is judged with the help of reactivity series. In this series, the metals lying above are more reactive than the metals which lie below in the series.

For the reaction of solid lithium metal and nitric acid, the equation follows:

3Li(s)+4HNO_3(aq.)\rightarrow 3LiNO_3(aq.)+2H_2O(l)+NO(g)

This is a type of single replacement reaction because Lithium (more reactive metal) is replacing Hydrogen (less reactive metal) from the chemical reaction.

3 0
2 years ago
How many moles of CaO are needed to react with excess water to produce 370g of calcium hydroxide?
never [62]

Answer:

5 moles

Explanation:

CaO+H20--> Ca(OH)2

mass 280 90 370g

RFM 56 18 74

moles 5 5 5

4 0
3 years ago
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