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neonofarm [45]
3 years ago
6

T OR F

Chemistry
1 answer:
Murljashka [212]3 years ago
5 0

Answer:

The statement is  false. See the explanation below, please.

Explanation:

The hydrogen bond or bridge is a type of dipole-dipole interaction that is generated from the attraction of a hydrogen atom and a very electronegative atom (oxygen, fluorine or nitrogen). Examples of hydrogen bridge molecules: Water (H20), ammonia (NH3).

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Why is cell division a<br> necessary function of living things?
Nady [450]
Because the older cells will not be able to function properly without the new cells taking over them. :)
6 0
3 years ago
Consider the following gas phase reaction:
snow_tiger [21]

Answer:

2NO(g) + O2(g) --> 2NO2(g)

now 400 ml of NO × 2 mol of NO2/2 mol of NO

= 400 ml of NO2

now 500 ml of O2 × 2 mol of NO2/1 mol of O2

= 1000 ml of NO2

now 400 ml of NO2 × 1 mol of O2/2 mol of NO

= 200 ml

subtract that from 500 ml of total i.e. 500-200 =300 ml

The total volume of the reaction mixture is 1000 ml -300ml = 700 ml

6 0
2 years ago
A gas occupies a volume of 1.00 L at 25.0°C. What volume will the gas occupy at 1.00 x10^2 °C?
Leno4ka [110]

Answer : The volume of gas occupy at 1.00\times 10^2^oC is, 1.25 L

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=1.00L\\T_1=25.0^oC=(25.0+273)K=298K\\V_2=?\\T_2=1.00\times 10^2^oC=((1.00\times 10^2)+273)K=373K

Putting values in above equation, we get:

\frac{1.00L}{298K}=\frac{V_2}{373K}\\\\V_2=1.25L

Therefore, the volume of gas occupy at 1.00\times 10^2^oC is, 1.25 L

3 0
3 years ago
The quantity, q grams, of the radioactive isotope strontium-90 present in a sample decreases by half over a period of about t =
velikii [3]
Notice q=3/2, is half of the original q = 3(<span>1/2</span>)<span>t/28.8
your welcome

</span>
8 0
3 years ago
Read 2 more answers
The Concentration of C6H12O6 May be represented as?
Amiraneli [1.4K]

Answer:

A 12 oz Coca Cola contains 39g of sugar or C6H12O6. 

To calculate for the molarity of sugar in the soda, convert 39 grams of sugar to moles sugar:

39g/ 180.16 g/mol = 0.216 mol sugar

then, convert 12 oz to L:

12oz / (1oz/0.02957L) = 0.35484 L

therefore the concentration of sugar in the soda is:

M = mol sugar / L sol'n

   = 0.216 mol sugar / 0.35484 L

   = 0.609 M

Explanation:

6 0
3 years ago
Read 2 more answers
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