2 years ago

Please help fast please please

Chemistry

1 answer:

deff fn [24]2 years ago

7 0

Answer:

crome .comxbdbshshdhdgsvsgsvdhjsjfskkt

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The atomic number of an atom is always equal to the total number of

Basile [38]

C is correct. Have a good day!

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2 years ago

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A sample of O2 gas occupies a volume of 571 mL at 26 ºC. If pressure remains constant, what would be the new volume if the tempe

Vlad1618 [11]

Answer: The new volume at different given temperatures are as follows.

(a) 109.81 mL

(b) 768.65 mL

(c) 18052.38 mL

Explanation:

Given: $V_{1}$ = 571 mL, $T_{1} = 26^{o}C$

(a) $T_{2} = 5^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{5^{o}C}\\V_{2} = 109.81 mL$

(b) $T_{2} = 95^{o}F$

Convert degree Fahrenheit into degree Cesius as follows.

$(1^{o}F - 32) \times \frac{5}{9} = ^{o}C\\(95^{o}F - 32) \times \frac{5}{9} = 35^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{35^{o}C}\\V_{2} = 768.65 mL$

(c) $T_{2} = 1095 K = (1095 - 273)^{o}C = 822^{o}C$

The new volume is calculated as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{822^{o}C}\\V_{2} = 18052.38 mL$

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2 years ago

What is the mass of OH- in Ca(OH)2

Ne4ueva [31]

Oxygen: 16.00 g/mol
Hydrogen: 1.01 g/mol

The mass would be 17.01 g/mol

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Which of the following is not a function?

EastWind [94]

Answer:

A student's name paired with the sport that they play.

Explanation:

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what term describes when a solvent is holding as much solute in solution as it is able for a given temperature

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The term that describes when a solvent is holding as much solute in solution as it is able for a given temperature is called supersaturated solution. A little disturbance to this solution some of the solute will crystallize or precipitate out since this solution is not stable.

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