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kvasek [131]
3 years ago
14

Please help fast please please

Chemistry
1 answer:
deff fn [24]3 years ago
7 0

Answer:

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3 0
3 years ago
Starting from a 1 M stock of NaCl, how will you make 50 ml of 0.15 M NaCl?
WARRIOR [948]

Answer:

We need 7.5 mL of the 1M stock of NaCl

Explanation:

Data given:

Stock = 1M this means 1 mol/ L

A 0.15 M solution of 50 mL has 0.0075 moles NaCl per 50 mL

Step 2: Calculate the volume of stock we need

The moles of solute will be constant

and n = M*V  

M1*V1 = M2*V2

⇒ with M1 = the initial molair concentration = 1M

⇒ with V1 = the volume we need of the stock

⇒ with V2 = the volume we want to make of the new solution = 50 mL = 0.05 L

⇒ with M2 = the concentration of the new solution = 0.15 M

1*V1 = 0.15*(50)

V1 = 7.5 mL

Since 0.0075 L of 1M solution contains 0.0075 moles

50 mL solution will contain also 0.0075 moles but will have a molair concentration of 0.0075 moles / 0.05 L =0.15 M

We need 7.5 mL of the 1M stock of NaCl

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3 years ago
How many bonds does CIO3- have, the chlorate ion have?
chubhunter [2.5K]
2 ions in that solution.
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What process takes place when hydrogen-3 and hydrogen-2 combine to form
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A. Fusion

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Which is the best description of the chemical reaction shown here in aqueous solution? ch3ch2cooh (aq) ↔ ch3ch2coo- (aq) + h+ (a
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The given reaction: 
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is called a reversible reaction.

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6 0
3 years ago
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