Ka is the equilibrium constant for the ionization for a reaction. It is calculated as follows
ka is equal to (H3o ions)(A-) divided by (HA)
2.00x106i s equal to 0.153x0.153 divided by ( HA)
(2.00x106)HA is equal to 0.023409
HA concentration is therefore equal to 0.023409/2.00x106 which is 1.104x10^-4moles/litre
Answer:
Sort the lab chemicals in alphabetical order for quick access.
Become familiar with the chemicals to be used, including exposure or spill hazards.
Locate the spill kits and understand how they are used.
Explanation:
There are many chemicals in a laboratory hence they should be sorted out and arranged in alphabetical order so that theory can easily be identified and located whenever they are required.
The properties of each chemical should be known especially hazards connected to exposure or spill of the chemicals.
The students should also familiarize themselves with the contents of spill kits and how they are used.
The total mass is the sum of the masses.
It is
5543 + 23.45 + 697.4 mg = 6263.85 mg
Answer: 6263.85 mg
