When a positive electrical charge comes in contact with a neutral electrical charge what happens?

When a 25000-kg fighter airplane lands on the deck of the aircraft carrier, the carrier sinks 0.23cm deeper into the water.

Genrish500 [490]

Answer:

10604 square meters

Explanation:

0.23 cm = 0.0023m

Assume the carrier has a shape of a rectangular box. When the carrier sinks 0.0023m deeper into water, the extra volume submerged into water is the same as the extra water volume being replaced. This extra volume would add an additional buoyant force to counter balance the extra weight created by the 25000 kg fighter.

With g being constant, the mass of the extra water displaced is the same as the mass of the fighter airplane $m_f$ . And mass of the water displaced is its volume V times its density $\rho$

$V\rho = m_f$

$1025V = 25000$

$V = 25000/1025 = 24.39 m^3$

We assume the carrier has a shape of a rectangular box, so this extra displaced volume is the extra depth d = 0.0023 m times cross-section area A

$V = dA$

$24.39 = 0.0023A$

$A = 24.39 / 0.0023 = 10604 m^2$

4 0

3 years ago

The fact that desert sand is very hot in the day and very cold at night is evidence that sand has

insens350 [35]

Answer:

A) a low specific heat.

Explanation:

As we know that heat given to the sand will increase it temperature

so we can say

$Q = ms\Delta T$

here we will have

$\Delta T = \frac{Q}{ms}$

so now we will have

more change in temperature due to heat given to the sand will show that it must have low specific heat capacity as it inversely depends on the specific heat capacity of the sand

so correct answer will be

A) a low specific heat.

5 0

3 years ago

Read 2 more answers

A gas‑forming reaction produces 1.90 m 3 1.90 m3 of gas against a constant pressure of 179.0 kPa. 179.0 kPa. Calculate the work

goldfiish [28.3K]

Answer:

The work done is 3.4 × 10⁵ J.

Explanation:

Given:

Pressure of the gas produced (P) = 179 kPa

Volume of the gas produced (ΔV) = 1.90 m³

We need to find the work done in joules. For that, we don't need any conversion as the units are already in SI units which will give the result in Joules only.

Now, let us verify our results by using conversion factors and without using them.

Using conversion factors:

1 m³ = 1000 L

So, 1.90 m³ = 1.90 m³ × 1000 $\frac{L}{m^3}$ = 1900 L